Answer:
To calculate the volume we must first find the number of moles
Number of moles (n ) = mass / Molar mass (M)
Since oxygen is diatomic
M of oxygen = 16 × 2 = 32g/mol
n = 16 / 32 = 0.5mol
Next we use the formula
V = n × V(dm³)
where V is the volume
V(dm³) is the volume of 1 mole of a substance at s.t.p which is
22.4dm³
Volume of oxygen gas at s.t.p is
0.5 × 22.4dm³
= 11.20dm³
Hope this helps you
Answer:
some of them not believe in God
Answer:
C) the relative number of moles taking part in the reaction
Explanation:
From a balanced chemical equation, it is always possible to determine the relative number of moles taking part in a chemical reaction.
The number of moles is the amount of the reacting specie that makes up a chemical reaction.
- In balanced chemical equation, the number of moles of reactants and products must be the same.
- From this understanding, we can determine the amount of reactants and products needed for a chemical reaction to take place.
We will assume complete dissociation.
Since we have the molarity of OH solution, we can calculate the p(OH) as follows:
p(OH) = -log(molarity of OH) = -log(<span>7.5×10-3) = 2.1249
It is known that: p(H) + p(OH) = 14
Therefore, p(H) can be calculated as follows:
p(H) = 14 - p(OH) = 14 - 2.1249 = 11.875</span>
First write all of the compounds/atoms in either side then fill in existing values and balance
Na- 1
Br- 1
Ca- 1
Cl- 2
Na- 1
Cl- 1
Ca-1
Br-2
Balance to get
2NaBr+CaCl2=2NaCl+CaBr2
