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frosja888 [35]
3 years ago
11

In the reaction of a carbonyl compound with silver cyanide, the lone pair of electrons on the nitrogen are the one that attack t

he carbonyl carbon. But if a carbonyl compound reacts with hydrogen cyanide, the cyanide ions directly attacks the carbonyl carbon. Explain why this happens??​
Chemistry
2 answers:
Marina CMI [18]3 years ago
7 0

Answer:

For Silver cyanide: Silver is more electropositive. Therefore no need for silver cyanide to split into silver ion and cyanide ion, only the lone pair of electrons from nitrogen atom will be attracted to the carbonyl carbon of the aldehyde or ketone.

For hydrogen cyanide: Hydrogen is less electropositive. Therefore hydrogen cyanide splits into hydrogen ion and cyanide ion, since cyanide ion is negative, It will be directly attracted to the carbonyl compound.

Equations: [ considering a ketone and aldehyde ]

RCHO + HCN → RCHCN + H2O

R'COCH3 + AgCN → R'C(CN)CH3 + Ag + H2O

.

.

never [62]3 years ago
3 0

Answer:

The larvae of mosquitoes live in water and provide food for fish and other wildlife, including larger larvae of other species such as dragonflies. The mosquito larvae themselves consume a lot of organic matter in wetlands, helping recycle nutrients back into the ecosystem.Ramabai Bhimrao Ambedkar was the first wife of B. R. Ambedkar, who said her support was instrumental in helping him pursue his higher education and his true potential. She has been the subject of a number of biographical movies and books. A number of landmarks across India have been named after her.Hydrochloric acid: HCl. Nitric acid: HNO. Phosphoric acid: H3PO. Sulfuric acid: H2SO.

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The ΔHsoln is _____.
nydimaria [60]

Sometimes negative sometimes positive, your answer is B!

4 0
3 years ago
Tris is a molecule that can be used to prepare buffers for biochemical experiments. It exists in two forms: Tris (a base) and Tr
ale4655 [162]

Solution :

For the reaction :

$\text{TrisH}^+ + H_2O \rightarrow \text{Trish}^- + H_3O^+$

we have

$Ka = \frac{[\text{Tris}^- \times H_3O]}{\text{Tris}^+}$

   $=\frac{x^2}{0.02 -x}$

  $=8.32 \times 10^{-9}$

Clearing $x$, we have $x = 1.29 \times 10^{-5} \text{ moles of acid}$

So to reach $\text{pH} = 7.8 (\text{pOH}= 14-7.8=6.2)$, one must have the $\text{OH}^-$ concentration of the :

$\text{[OH}^-]=10^{-pOH} = 6.31 \times 10^{-7} \text{ moles of base}$

So we can add enough of 1 M NaOH in order to neutralize the acid that is calculated above and also adding the calculated base.

$\text {n NaOH}=1.29 \times 10^{-5}+6.31 \times 10^{-7}$

            $= 1.35 \times 10^{-5} \text{ moles}$

Volume NaOH $= 1.35 \times 10^{-5} \text{ moles} \times \frac{1000 \text{ mL}}{1 \text{ mol}} = 0.0135 \text{ mL}$

Tris mass $H^+ = 0.02 \text{ mol} \times 157.6 \text{ g/mol}=3.152 \text{ g}$

Now to prepare the said solution we must mix:

$3.152 \text{ g Tris H} + 0.0135 \text{ mL NaOH} \ 1 M$ gauge to 1000 mL with water.

3 0
3 years ago
Explain why most metals are malleable and ductile but ionic crystals are not
Dima020 [189]
Throughout the metallic structure allowing the atoms to slide past each other. This sliding is why metals are ductile and malleable. Ioniccompound must break bonds to slide past one another, which causes the ionic material to split and crack.
7 0
3 years ago
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what mass of sodium fluoride (FW=42.0 g/mol) must be added to 3.50 x 10^2 mL of water to give a solution with pH = 8.40?
MaRussiya [10]

Answer:

Explanation:

Sodium fluoride, being a salt, dissolves in water completely producing F ⁻ ions. Now  F⁻ is the conjugate base of the weak acid HF, so in water we will have the following equilibrium:

F⁻  +  H₂O ⇆ HF + OH⁻

Given this equilibrium, we need to calculate Kb from the Ka for HF,  the [ OH ⁻] from the given pH, and finally the mass needed to produce that  OH⁻ concentration.  

The equilibrium constant, Kb , can be calculated from Kw = Ka x Kb, where Kw = 10⁻¹⁴ and Ka for HF is  6.6 x 10⁻⁴ from reference tables.

Kb = 10⁻¹⁴ / 6.6 x 10⁻⁴ = 1.5 x 10⁻¹¹

pH + pOH = 14  ⇒ pOH = 14 - 8.40 = 5.60

[ OH⁻ ] = 10^-5.60 = 2.51 x 10⁻⁶

Now we have all the information :

                                   F⁻                    HF                        OH⁻

Equilibrium                 X                  2.51 x 10⁻⁶            2.51 x 10⁻⁶

(2.51 x 10⁻⁶)² / X  =  1.5 x 10⁻¹¹     ⇒  X =  (2.51 x 10⁻⁶)²  / 1.5 x 10⁻¹¹

X = [ F⁻ ] = 0.41 M

For 350 mL ( 0.35 L ) we need to add:

0.41 mol HF/ 1 L  *  0.35 L = 0.144 mol

and finally the mass will be:

0.144 mol NaF *  42.0 g/mol NaF = 6.03 g NaF

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3 years ago
What is 0.0745 in scientific notation?
katen-ka-za [31]

Answer:

7.45 × 10^{-2}

Explanation:

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