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Diano4ka-milaya [45]
2 years ago
9

A mixture of 2.0 mol of CO(g)? and 2 mol of H2O?(g)? was allowed to come to equilibrium in a 1.0L flask at a high temperature. I

f Kc?=4.0, what is the molar concentration of H2(g) in the equilibrium mixture: CO(g) + H2O(g)\rightleftharpoons CO2(g) +H2(g)
Chemistry
1 answer:
Bess [88]2 years ago
7 0

For a mixture of 2.0 mol of CO(g) and 2 mol of H2O(g) was allowed to come to equilibrium in a 1.0L flask at a high temperature. the molar concentration of H2(g)  is mathematically given as

[H2] = x = 1.33 M

<h3>What is the molar concentration of H2(g) in the equilibrium mixture?</h3>

Generally, the equation for the Chemical reaction  is mathematically given as

Kc = [CO2]*[H2]/[CO]*[H2O]

Therefore

4.0 = (1*x)^2/(2-1*x)^2

x = 1.33

In conclusion, the molar concentration

[H2] = x = 1.33 M

Read more about  Chemical reaction

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Which statement best describes a physical change?
Inga [223]

Answer:  3 Changes can occur to physical properties of a substance, but the chemical composition of the substance remains the same

Explanation:

Physical change mainly physical properties of a substance while the chemical changes remain unchanged. Once there is a change to the chemistry of the substance, this would be classified as a chemical change.

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A and b are two gases that are mixed together: 2.50 mol a is mixed with 0.850 mol b. if the final pressure of the mixture is 1.7
USPshnik [31]

Partial pressure of gas A is 1.31 atm and that of gas B is 0.44 atm.

The partial pressure of a gas in a mixture can be calculated as

Pi = Xi x P

Where Pi is the partial pressure; Xi is mole fraction and P is the total pressure of the mixture.

Therefore we have Pa = Xa x P and Pb = Xb x P

Let us find Xa and Xb

Χa = mol a/ total moles = 2.50/(2.50+0.85) = 2.50/3.35 = 0.746

Xb = mol b/total moles = 0.85/(2.50+0.85) = 0.85/3.35 = 0.254

Total pressure P is given as 1.75 atm

Pa = Xa x P = 0.746 x 1.75 = 1.31atm

Partial pressure of gas A is 1.31 atm

Pb = Xb x P = 0.254 x 1.75 = 0.44atm

Partial pressure of gas B is 0.44 atm.

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6 0
2 years ago
Draw a sodium formate molecule. The structure has been supplied here for you to copy. To add formal charges, click the button be
Karo-lina-s [1.5K]

The Molecule of Sodium Formate along with Formal Charges (in blue) and lone pair electrons (in red) is attached below.

Sodium Formate is an ionic compound made up of a positive part (Sodium Ion) and a polyatomic anion (Formate).

Nomenclature:

                       In ionic compounds the positive part is named first. As sodium ion is the positive part hence, it is named first followed by the negative part i.e. formate.

Name of Formate:

                             Formate ion has been derived from formic acid ( the simplest carboxylic acid). When carboxylic acids looses the acidic proton of -COOH, they are converted into Carboxylate ions.

E.g.

                    HCOOH (formic acid)    →     HCOO⁻ (formate)  +  H⁺

                H₃CCOOH (acetic acid)     →      H₃CCOO⁻ (acetate)  +  H⁺

Formal Charges:

                           Formal charges are calculated using following formula,

          F.C  =  [# of Valence e⁻] - [e⁻ in lone pairs + 1/2 # of bonding electrons]

For Oxygen:

                    F.C  =  [6] - [6 + 2/2]

                    F.C  =  [6] - [6 + 1]

                    F.C  =  6 - 7

                    F.C  =  -1

For Sodium:

                    F.C  =  [1] - [0 + 0/2]

                    F.C  =  [1] - [0]

                    F.C  =  1 - 0

                    F.C  =  +1

5 0
3 years ago
When iron metal reacts with oxygen, the reaction can form Fe2O3. Write a balanced chemical equation for this reaction, and find
I am Lyosha [343]
<h3>Answer:</h3>

Balanced equation: 4Fe + 3O₂ → 2Fe₂O₃

Moles of oxygen gas = 9 moles

<h3>Explanation:</h3>

To answer the question;

  • We first write the balanced equation between iron metal and Oxygen
  • The balanced equation is given as;

4Fe + 3O₂ → 2Fe₂O₃

  • We are given 6 moles of Fe₂O₃

We are required to determine the number of moles of oxygen needed to form 6 moles of Fe₂O₃.

  • From the equation, 3 moles of oxygen gas reacts to produce 2 moles of Fe₂O₃
  • This means, the mole ratio of O₂ to Fe₂O₃ is 3 : 2

Therefore; Moles of O₂ = Moles of Fe₂O₃ × 3/2

Hence, moles of oxygen = 6 moles × 3/2

                                         = 9 moles

Thus, Moles of Oxygen needed is 9 moles

6 0
3 years ago
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