Answer:
0.733 J/g °C
Explanation:
<u>Step 1 : Write formule of specific heat</u>
<u />
Q
=
mc
Δ
T
with Q = heat transfer (J)
with m = mass of the substance
with c = specific heat ⇒ depends on material and phase ( J/g °C)
Δ
T = Change in temperature
<u />
in this case :
Q = 38.5 J
<u>m = 17.5g</u>
<u>c= has to be determined</u>
<u>Δ
T = 3 (°C)</u>
<u />
<u>Step 2: Calculating specific heat</u>
⇒ via the formule Q
=
mc
Δ
T
38.5 J = 17.5g * c * 3
38.5 = 52.5 *c
c = 38.5 / 52.5
c = 0.733 J/g °C ⇒ 0.733 is reported to three significant digits due to the precision.
The specific heat of this metal is 0.733 J/g °C
Answer:
C) 1.15 × 10⁻⁷ mm
Explanation:
Step 1: Given data
Average distance between nitrogen and oxygen atoms: 115 pm
Step 2: Convert the distance to meters (SI base unit)
We will use the conversion factor 1 m = 10¹² pm.
115 pm × (1 m/10¹² pm) = 1.15 × 10⁻¹⁰ m
Step 3: Convert the distance to millimeters
We will use the conversion factor 1 m = 10³ mm.
1.15 × 10⁻¹⁰ m × (10³ mm/1 m) = 1.15 × 10⁻⁷ mm
In a permanent magnet, a magnetic field is produced by the composite motions of electrons in geometrically aligned atoms.
A magnetic field is characterized by poles called north and south. Magnetic polarity refers to the orientation of these poles in space.
