464 g radioisotope was present when the sample was put in storage
<h3>Further explanation</h3>Given
Sample waste of Co-60 = 14.5 g
26.5 years in storage
Required
Initial sample
Solution
General formulas used in decay:
t = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
Half-life of Co-60 = 5.3 years
Input the value :
Answer:
Explanation:
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In this case, since the integrated rate law for a second-order reaction is:
Thus, we plug in the initial concentration, rate constant and elapsed time to obtain:
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Answer:
Explanation:
a. CuO+ 2HCl⇒CuCl2+ H2O
b. =
= 0,05 (mol)
⇒=
=0,05 mol
⇒= 0,05×135=6,75 (g)
c. =2×
=0,1 (mol)
⇒= 0,1×36,5= 3,65 (g)
⇒=
×100=36,5 (g)
⇒ Nồng độ phần trăm dd sau phản ứng= Nồng độ % dd CuCl2=×100=
×100≈ 16,67%