Idk honestly just tryna get points.
Answer:
Encouraging your preschooler’s creative play
For your preschooler, time, materials and space to be creative are very important.
Preschoolers like to be spontaneous in their creative play, so it’s good to follow your child’s lead. But there’ll also be times when your child wants you to be more involved in her creative activities. By being actively involved, you can develop your child’s skills and understanding.
Answer:
Is very important to employ safety and care
For every staff
Is very necessary is protected
Her is going very high stage
Because of every one say that this company is best for others company
Is reason safety is very important in our life
<h3 /><h3><em>I hope</em><em> </em><em>you like</em><em> </em><em>it</em><em> </em></h3>
Complete Question
Consider a single crystal of some hypothetical metal that has the BCC crystal structure and is oriented such that a tensile stress is applied along a [121] direction. If slip occurs on a (101) plane and in a [111] direction, compute the stress at which the crystal yields if its critical resolved shear stress is 2.9 MPa.
Answer:
The stress is 
Explanation:
From the question we are told that
The critical yield resolved shear stress is 
First we obtain the angle
between the slip direction [121] and [111]
![\lambda = cos^{-1} [\frac{(u_1 u_2 + v_1 v_2 + w_1 w_2}{\sqrt{u_1^2 + v_1 ^2+ w_1^2})\sqrt{( u_2^2 + v_2^2 + w_2 ^2)} } ]](https://tex.z-dn.net/?f=%5Clambda%20%3D%20cos%5E%7B-1%7D%20%5B%5Cfrac%7B%28u_1%20u_2%20%2B%20v_1%20v_2%20%2B%20w_1%20w_2%7D%7B%5Csqrt%7Bu_1%5E2%20%2B%20v_1%20%5E2%2B%20w_1%5E2%7D%29%5Csqrt%7B%28%20u_2%5E2%20%2B%20v_2%5E2%20%2B%20w_2%20%5E2%29%7D%20%7D%20%20%5D)
Where
are the directional indices
![\lambda = cos ^-[ \frac{(1) (-1) + (2) (1) + (1) (1)}{\sqrt{((1)^2 +(2)^2 + (1)^2)}\sqrt{((-1)^2 + (1)^2 + (1)^2 ) } } ]](https://tex.z-dn.net/?f=%5Clambda%20%20%3D%20%20cos%20%5E-%5B%20%5Cfrac%7B%281%29%20%28-1%29%20%2B%20%282%29%20%281%29%20%2B%20%281%29%20%281%29%7D%7B%5Csqrt%7B%28%281%29%5E2%20%2B%282%29%5E2%20%2B%20%281%29%5E2%29%7D%5Csqrt%7B%28%28-1%29%5E2%20%2B%20%281%29%5E2%20%2B%20%281%29%5E2%20%29%20%7D%20%20%7D%20%5D)
![= cos^{-1} [\frac{2}{\sqrt{6} \sqrt{3} } ]](https://tex.z-dn.net/?f=%3D%20cos%5E%7B-1%7D%20%5B%5Cfrac%7B2%7D%7B%5Csqrt%7B6%7D%20%5Csqrt%7B3%7D%20%20%7D%20%5D)
Next is to obtain the angle
between the direction [121] and [101]
![\O = cos^{-1} [\frac{(u_1 u_3 + v_1 v_3 + w_1 w_3}{\sqrt{u_1^2 + v_1 ^2+ w_1^2})\sqrt{( u_3^2 + v_3^2 + w_3 ^2)} } ]](https://tex.z-dn.net/?f=%5CO%20%3D%20cos%5E%7B-1%7D%20%5B%5Cfrac%7B%28u_1%20u_3%20%2B%20v_1%20v_3%20%2B%20w_1%20w_3%7D%7B%5Csqrt%7Bu_1%5E2%20%2B%20v_1%20%5E2%2B%20w_1%5E2%7D%29%5Csqrt%7B%28%20u_3%5E2%20%2B%20v_3%5E2%20%2B%20w_3%20%5E2%29%7D%20%7D%20%20%5D)
Substituting 1 for
, 2 for
, 1 for
, 1 for
, 0 for
, and 1 for 
![\O = cos^{-1} [\frac{1* 1 + 2*0 + 1*1 }{\sqrt{1^2 + 2^2 + 1^2 } \sqrt{(1^2 + 0^2 + 1^2 )} } ]](https://tex.z-dn.net/?f=%5CO%20%3D%20cos%5E%7B-1%7D%20%5B%5Cfrac%7B1%2A%201%20%2B%202%2A0%20%2B%201%2A1%20%7D%7B%5Csqrt%7B1%5E2%20%2B%202%5E2%20%2B%201%5E2%20%7D%20%5Csqrt%7B%281%5E2%20%2B%200%5E2%20%2B%201%5E2%20%29%7D%20%20%7D%20%5D)
![\O = cos^{-1} [\frac{2}{\sqrt{6} \sqrt{2} } ]](https://tex.z-dn.net/?f=%5CO%20%3D%20cos%5E%7B-1%7D%20%5B%5Cfrac%7B2%7D%7B%5Csqrt%7B6%7D%20%5Csqrt%7B2%7D%20%20%7D%20%5D)

The stress is mathematically represented as



