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Debora [2.8K]
3 years ago
6

It's in the picture please asap

Engineering
2 answers:
vodomira [7]3 years ago
8 0
Screen is blank!! Sorry I couldn’t help you
Dennis_Churaev [7]3 years ago
7 0
the screen is blank bro
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Explain what a stress-concentration is and how it can be accounted for in the design and analysis of a structural component. Be
Mama L [17]

Answer:

Stress-concentration

        In the machine component the stress become concentrate at the point a particular point and due to this crack formation takes places and after some time some the machine component become fails.High stress concentration means high stress at that point.

It is very important in the design point of view because we have to find out where stress concentration is high and needs to take proper factor of safety to avoid the failure of the machine component.Generally at sharp corner,sudden change and complex shapes stress concentration is high.

3 0
3 years ago
25°C is flowing in a covered irrigation ditch below ground. Every 100 ft, there is a vent line with a 1.0 in. inside diameter an
Gnesinka [82]

The total evaporation loss of water is 87.873 ×10^{-5}  lbm /day.

<u>Explanation:</u>

Assume A is the water and B is air.

A is diffusing to non diffusing B.

N_{A}=\frac{D_{A B} P}{R T Z P_{B/ M}}\left(P_{A_{1}} \ - P_{B_{2}}\right)

By the table 6.2 - 1 at 25°C, the diffusivity of air and water system is 0.260 \times 10^{-4} \mathrm{m}^{2} / \mathrm{s}.

Total pressure P = 1 atm = 101.325 KPa

P_{A_{1} } = 23.76 mm Hg

P_{A_{1} } = \frac{23.76}{760}

P_{A_{1} } = 0.03126 atm

P_{A_{1} } = 3.167 K Pa

When air surrounded is dry air, then PA_{2} = 0 mm Hg

R = 8.314 \frac{K P a \cdot m^{3}}{mol \cdot k}

P_{B/M} = \frac{P_{B_{1}}-P_{B_{2}}}{\ln \left(P_{B_{1}} / P_{B_{2}}\right)}

P_{B_{1}}=P_{T}-P_{A1_{}}

= 101.325 - 3.167

P_{B_{1} } = 98.158 K Pa

P_{B_{2}}=P_{T}-P_{A_{2}}

P_{B_{2} } = 101.325 - 0

P_{B_{2} } = 101.325 K Pa

P_{B / M}=\frac{98.158-101.325}{\ln (98.158 / 101 \cdot 325)}

P_{B/M} = 99.733 K Pa

Z = 1 ft = 0.3048 m

T = 298 K

N_{A} =  \frac{(0.206*10^{-4})(101.325)(3.167 - 0) }{(8.314) ( 298 )( 0.3048 )( 99.733 ) }

N_{A} = 0.11077 × 10^{-6} mol/ m^{2}.s

N_{A} = 0.11077 × 10^{-6} × 18 × (60×60×24)

N_{A} = 0.1723 lb_{m} / m^{2}.day

\tilde{N}_{A}=N_{A} \times Area

Area of individual pipe is

A=\frac{\pi}{4}(0.0254)^{2}

A = 0.00051 m^{2}

\bar{N}_{\boldsymbol{A}} = 0.1723 × 0.00051

\bar{N}_{\boldsymbol{A}} = 0.000087873 lbm/day

In 1000 ft length of ditch,there will be a 10 pipes. The amount of evaporation water is

= 10 × 0.000087873 = 0.00087873 lbm /day

The total evaporation loss of water is 87.873 ×10^{-5}  lbm /day.

5 0
3 years ago
53. The plan of a building is in the form of a rectangle with
schepotkina [342]

Answer: 150m

Explanation:

The following can be depicted from the question:

Dimensions of outer walls = 9.7m × 14.7m.

Thickness of the wall = 0.30 m

Therefore, the plinth area of the building will be:

= (9.7 + 0.30/2 + 0.30/2) × (14.7 × 0.30/2 + 0.30/2)

= 10 × 15

= 150m

7 0
3 years ago
Everyone has only one learning style. True or false? hurry pleasle this exp carees class
Temka [501]

Answer:

This is False because people can have more than 1

7 0
3 years ago
Jnjn freeeeeeeeeeeeeeeeeeeeeeeeeeeeeee pointtttttttttt
kvasek [131]

Answer:

thx

Explanation:

5 0
3 years ago
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