Answer:
0.7μM = 0.6 μM = 0.5 μM > 0.4 μM > 0.3 μM > 0.2 μM
Explanation:
An enzyme solution is saturated when all the active sites of the enzyme molecule are full. When an enzyme solution is saturated, the reaction is occurring at the maximum rate.
From the given information, an enzyme concentration of 1.0 μM Y can convert a maximum of 0.5 μM AB to the products A and B per second means that a 1.0 M Y solution is saturated when an AB concentration of 0.5 M or greater is present.
The addition of more substrate to a solution that contains the enzyme required for its catalysis will generally increase the rate of the reaction. However, if the enzyme is saturated with substrate, the addition of more substrate will have no effect on the rate of reaction.
<em>Therefore the reaction rates at substrate concentrations of 0.7μM, 0.6 μM, and 0.5 μM are equal. But the reaction rate at substrate concentrations of 0.2 μM is lower than at 0.3 μM, 0.3 μM is lower than 0.4 μM and 0.4 μM is lower than 0.5 μM, 0.6 μM and 0.7 μM.</em>
Answer:
Partial pressure SO₂ → 0.440 atm
Explanation:
We apply the mole fraction concept to solve this:
Moles of gas / Total moles = Partial pressure of the gas / Total pressure
Total moles = 0.3 moles of CO₂ + 0.2706 moles of SO₂ + 0.35 moles H₂O
Total moles = 0.9206 moles
Mole fraction SO₂ = 0.2706 moles / 0.9206 moles → 0.29
Now, we can know the partial pressure:
0.29 = Partial pressure SO₂ / Total pressure
0.29 = Partial pressure SO₂ / 1.5 atm
0.29 . 1.5atm = Partial pressure SO₂ → 0.440 atm
