Answer:
Separation between the plates, area of the plates and dielectric constant
Explanation:
The capacitance of a parallel plate capacitor is given by:

where
k is the dielectric constant
is the vacuum permittivity (which has a constant value)
A is the area of the plates
d is the separation between the plates
Therefore from the formula we see that the capacitance of a parallel plate capacitor depends on the following factors:
- Separation between the plates
- Area of the plates
- Dielectric constant
To solve this problem we will apply the concepts related to the centripetal Force and the Force given by weight and formulated in Newton's second law. Through the two expressions we can find the radius of curve made in the hand. To calculate the normal force, we will include the concepts of sum of forces to obtain the net force on the body at the top and bottom of the maneuver. The expression for centripetal force acting on the jet is

According to Newton's second law, the net force acting on the jet is
F = ma
Here,
m = mass
a = acceleration
v = Velocity
r = Radius
PART A ) Equating the above two expression the equation for radius is


Replacing with our values we have that
![r = \frac{(1140km/hr[\frac{1000m}{1km}\frac{1hour}{3600s}])^2}{7(9.8m/s^2)}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B%281140km%2Fhr%5B%5Cfrac%7B1000m%7D%7B1km%7D%5Cfrac%7B1hour%7D%7B3600s%7D%5D%29%5E2%7D%7B7%289.8m%2Fs%5E2%29%7D)

PART B )
<u>- The expression for effective weight of the pilot at the bottom of the circle is</u>

![N = (69kg)(9.8m/s^2)+\frac{(69)(1140km/hr[\frac{1000m}{1km}\frac{1hour}{3600s}])^2}{1.462*10^3m}](https://tex.z-dn.net/?f=N%20%3D%20%2869kg%29%289.8m%2Fs%5E2%29%2B%5Cfrac%7B%2869%29%281140km%2Fhr%5B%5Cfrac%7B1000m%7D%7B1km%7D%5Cfrac%7B1hour%7D%7B3600s%7D%5D%29%5E2%7D%7B1.462%2A10%5E3m%7D)

<em>Note that the normal reaction N is directed upwards and gravitational force mg is directed downwards. At the bottom of the circle, the centripetal force is directed upwards. So the centripetal force is obtained from the gravitational force and the normal reaction. </em>
<u>- The expression for effective weight of the pilot at the top of the circle is</u>

![N = (69kg)(9.8m/s^2)-\frac{(69)(1140km/hr[\frac{1000m}{1km}\frac{1hour}{3600s}])^2}{1.462*10^3m}](https://tex.z-dn.net/?f=N%20%3D%20%2869kg%29%289.8m%2Fs%5E2%29-%5Cfrac%7B%2869%29%281140km%2Fhr%5B%5Cfrac%7B1000m%7D%7B1km%7D%5Cfrac%7B1hour%7D%7B3600s%7D%5D%29%5E2%7D%7B1.462%2A10%5E3m%7D)

<em>Note that at the top of the circle the centripetal force is directed downwards. So the centripetal force is obtained from normal reaction and the gravitational force. </em>
Answer:
The answer is A
Explanation:
Independent variables don't have to depend on other factors of the experiment because they're independent
We know, speed = Distance / Time
d = 384,750 Km
t = 2 days, 19.5 hours = 48+19.5 = 67.5 hour
Substitute their values,
s = 384,750 / 67.5
s = 5700 Km/h
In short, Your Answer would be 5700 Km/h
Hope this helps!
Explanation:
For a charge concentrated nearly at a point, the electric field is directly proportional to the amount of charge; it is inversely proportional to the square of the distance radially away from the centre of the source charge and depends also upon the nature of the medium.