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valentinak56 [21]
3 years ago
11

2. A stone is thrown vertically upward with a speed of 22m/s.

Physics
1 answer:
Eduardwww [97]3 years ago
7 0

Answer:

Explanation:

Energy E is conserved:

E=\frac{1}{2}mv^2+mgh

If v₀ = 22m/s, h₀=0m and h₁=25m:

E=\frac{1}{2}mv_0^2=\frac{1}{2}mv_1^2+mgh_1

Solving for v₁:

v_1=\sqrt{v_0^2-2gh_1}

There is no real solution, because the stone never reaches 25m.

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3 years ago
A ball is thrown upward at time t=0 from the ground with an initial velocity of 8 m/s (~ 18 mph). What is the total time it is i
evablogger [386]

Answer:

The total time it is in the air for the ball is 1.6326 s

Given:

Initial velocity = 8 \frac{m}{s}

To find:

the total time it is in the air = ?

Formula used:

t = \frac{v-u}{a}

Where t = time to reach maximum height

v = final velocity of the ball = 0 m/s

u = initial velocity of ball = 8 m/s

a = acceleration due to gravity = -9.8

Acceleration of gravity is taken as negative because ball is moving in opposite direction.

Solution:

A ball is thrown upward at time t=0 from the ground with an initial velocity of 8 m/s.

The time taken by the ball to reach the maximum height is given by,

t = \frac{v-u}{a}

Where t = time to reach maximum height

v = final velocity of the ball = 0 m/s

u = initial velocity of ball = 8 m/s

a = acceleration due to gravity = -9.8

Acceleration of gravity is taken as negative because ball is moving in opposite direction.

t = \frac{0-8}{-9.8}

t = 0.8163 s

Thus, time taken by the ball to reach the ground again = time taken to reach maximum height

So, Total time required for ball to reach ground = 2t = 2 × 0.8163

Total time required for ball to reach ground = 1.6326 s

The total time it is in the air for the ball is 1.6326 s

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