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4 years ago

2. A stone is thrown vertically upward with a speed of 22m/s.

Physics

1 answer:

Eduardwww [97]4 years ago

7 0

Answer:

Explanation:

Energy E is conserved:

$E=\frac{1}{2}mv^2+mgh$

If v₀ = 22m/s, h₀=0m and h₁=25m:

$E=\frac{1}{2}mv_0^2=\frac{1}{2}mv_1^2+mgh_1$

Solving for v₁:

$v_1=\sqrt{v_0^2-2gh_1}$

There is no real solution, because the stone never reaches 25m.

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