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3 years ago

How is amplitude changed in an instrument or tuning fork

1 answer:

azamat3 years ago

7 0

Amplitude is affected by the energy wave in the instrument. High energy wave means high amplitude and low energy wave means low amplitude.

<u>Explanation:</u>

The amplitude of a periodic variable is a measure of its change over a single period. There are various definitions of amplitude, which are all functions of the magnitude of the differences between the variable's extreme values.

The amount of energy carried by a wave is related to the amplitude of the wave. Amplitude of an instrument is directly affected by the wave of the energy in the instruments. High energy wave means high amplitude and low energy wave means low amplitude in the instrument.

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What is the value of x? enter your answer in the box. Mm triangle v t k with segment t y such that y is on segment v k, between

Crank

Answer: 98 millimeters

Explanation:

Since angle VTY is congruent to angle VTK, segment TY bisects angle VTK. Since Y is on segment VK, between V and K, we can use the Angle Bisector Theorem, which states that

(1)

Since x= VK = VY + YK, we need to obtain VY since YK = 68.

VY is obtained by multiplying the denominator YK on both sides of equation (1). So,

Hence,

x = VK = VY + YK

x = 30 + 68

x = 98 millimeters

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2 years ago

A 20 kg bike accelerates at 10 m/s2. With what force was the person pedaling if friction

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3 years ago

Read 2 more answers

A volume V= 2.48 L of an ideal nitrogen gas (N2) are at temperature T= 0.964°C and pressure p = 1.49 atm.

Orlov [11]

Complete question:

A volume V= 2.48 L of an ideal nitrogen gas (N2) are at temperature T= 0.964°C and pressure p = 1.49 atm. Find the number of moles of the gas.

Answer:

The number of mole of the gas is 0.164 mol.

Explanation:

Given;

volume of the ideal gas, V = 2.48 L

temperature of the gas, T = 0.964 °C = 273K + 0.964 = 273.964 K

pressure of the gas, P = 1.49 atm

The number of moles of the gas is calculated by using ideal gas equation;

PV = nRT

where;

n is the number of moles of the gas

R is ideal gas constant = 0.082057 L.atm/mol.K

$n = \frac{PV}{RT} \\\\n = \frac{1.49 \ atm \ \times \ 2.48 \ L}{0.082057 \ L.atm/mol.K \ \ \times \ 273.964 \ K} \\\\n = 0.164 \ mol$

Therefore, the number of mole of the gas is 0.164 mol.

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3 years ago

A 2 kg block is sitting motionless on a ramp at 24° with the horizontal. What is the force of friction on the block that resists

vagabundo [1.1K]

Answer:

7.97 N

Explanation:

$f = m g sin(\alpha) = 2 * 9.8 * sin(24) = 7.97 N$

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3 years ago

A cart with mass 340 g moving on a frictionless linear air track at an initial speed of 1.2 m/s undergoes an elastic collision w

patriot [66]

Answer:

A) m2 = 98.71g

B) v_f2 = 1.86 m/s

Explanation:

We are given;

Mass of cart; m1 = 340g

Initial speed; v_i1 = 1.2 m/s

Final speed; v_f1 = 0.66 m/s

A)Since the collision is elastic, we can simply apply the conservation of momentum to get;

m1•(v_i1) = m1•(v_f1) + m2•(v_f2) - - - - - (eq1)

From conservation of kinetic energy, we have;

(1/2)m1•(v_i1)² = (1/2)m1•(v_f1)² + (1/2)m2•(v_f2)² - - - - eq(2)

Let's make v_f2 the subject in eq 2;

Thus,

v_f2 = √([m1•(v_i1)² - m1•(v_f1)²]/m2)

v_f2 = √([m1((v_i1)² - (v_f1)²)]/m2)

Let's put this for v_f2 in eq1 to obtain;

m2 = {m1((v_i1) - (v_f1))}/√([m1((v_i1)² - (v_f1)²)]/m2)

Let's square both sides to give;

(m2)² = {m1•m2((v_i1) - (v_f1))²}/([(v_i1)² - (v_f1)²]

This gives;

m2 = {m1((v_i1) - (v_f1))²}/([(v_i1)² - (v_f1)²]

Plugging in the relevant values to get;

m2 = {340((1.2) - (0.66))²}/([(1.2)² - (0.66)²]

m2 = 98.71g

B) from equation 1, we have;

m1•(v_i1) = m1•(v_f1) + m2•(v_f2)

Making v_f2 the subject, we have;

v_f2 = m1[(v_i1) - (v_f1)]/m2

Plugging in the relevant values to get;

v_f2 = 340[(1.2) - (0.66)]/98.71

v_f2 = 1.86 m/s

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3 years ago