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3 years ago

Eukaryotic cells can be unicellular and multicellular true or false

Physics

1 answer:

dimaraw [331]3 years ago

8 0

Yes, it can be unicellular and multicellular

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Light of wavelength 400 nm is incident on a single slit of width 15 microns. If a screen is placed 2.5 m from the slit. How far

olganol [36]

Answer:

0.0667 m

Explanation:

λ = wavelength of light = 400 nm = 400 x 10⁻⁹ m

D = screen distance = 2.5 m

d = slit width = 15 x 10⁻⁶ m

n = order = 1

θ = angle = ?

Using the equation

d Sinθ = n λ

(15 x 10⁻⁶) Sinθ = (1) (400 x 10⁻⁹)

Sinθ = 26.67 x 10⁻³

y = position of first minimum

Using the equation for small angles

tanθ = Sinθ = y/D

26.67 x 10⁻³ = y/2.5

y = 0.0667 m

5 0

3 years ago

A system of ideal gas at 22°C undergoes an ischoric process with an internal energy decrease of 4.30 × 10 3 4.30×103 J to a fina

Komok [63]

Answer:

The approximate change in entropy is -14.72 J/K.

Explanation:

Given that,

Temperature = 22°C

Internal energy $U=4.30\times10^{3}\ J$

Final temperature = 16°C

We need to calculate the approximate change in entropy

Using formula of the entropy

$\Delta S=\dfrac{\Delta U}{T}$

Where, $\Delta U$ = internal energy

T = average temperature

Put the value in to the formula

$\Delta S=\dfrac{-4.30\times10^{3}}{\dfrac{22+273+16+273}{2}}$

$\Delta S=-14.72\ J/K$

Hence, The approximate change in entropy is -14.72 J/K.

5 0

4 years ago

A ball initially at rest rolls down a hill with an acceleration of 3.3 m/s2. If it accelerates for 7.5 s, how far will it move?

goldfiish [28.3K]

<u>Answer:</u>

Ball will move 92.8125 meter along the cliff in 7.5 seconds.

<u>Explanation:</u>

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this case initial velocity = 0 m/s, acceleration = 3.3 $m/s^2$ , we need to calculate displacement when time = 7.5 seconds.

Substituting

$s=0*7.5+\frac{1}{2} *3.3*7.5^2\\ \\ =92.8125 meter$

So ball will move 92.8125 meter along the cliff in 7.5 seconds.

5 0

3 years ago

A drag racer starts from the rest and accelerates at 7.4m/s^2.how far will he travel in 2.0 seconds?

Vesna [10]

Answer:

14.8 m

Explanation:

S= ut + $\frac{1}{2}$ a $t^{2}$

where u = initial velocity

S= (0 $\frac{m}{s}$ )(2 $s$ ) + $\frac{1}{2}$ (7.4 $\frac{m}{s^{2} }$ )(2 $s^{2}$ )

S= $\frac{1}{2}$ (7.4 $\frac{m}{s^{2} }$ )(2 $s^{2}$ )

S=14.8 m

8 0

3 years ago

What I Know Directions: Read and understand the questions below. Choose the letter of the best answer, Write the chosen letter o

frozen [14]

Meter is the basic unit of distance

3 0

2 years ago