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mrs_skeptik [129]
2 years ago
10

The wavelengths of visible light vary from about 300 nm to 700 nm. What is the range of frequencies of visible light in a vacuum

Physics
1 answer:
exis [7]2 years ago
6 0

The range of frequencies  of visible light in a vacuum is mathematically given as

Fmin=4.19*10^14Hz  to Fmax=1*10^15Hz

<h3>What is the range of frequencies of visible light in a vacuum?</h3>

Question Parameters:

The wavelengths of visible light vary from about 300 nm to 700 nm.

Generally, the equation for the frequency   is mathematically given as

F=C/\lambda

Therefore

For Fmax

Fmax=\frac{300*10^8}{3*10^9}

Fmax=1*10^15Hz

Where

Fmin=\frac{3*10^8}{700*10^9}

Fmin=4.19*10^14Hz

For more information on Wave

brainly.com/question/3004869

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what is the ratio of ey,final, the maximum value of the y-component of the electric field immediately following the last polariz
OleMash [197]

That ratio is 2 .

<h3>What is ratio?</h3>

A ratio is the  comparison of the  two numbers bydivision.

Taking the first two outputs, or the  -1/8 and -1/4, we can divide not the second one by the first one to find the

ratio:

-1/4-1/8

When dividing fractions, we multiply by the reciprocal:

-1/4x-8/1

To multiply fractions, multiply straight across:

(-1x-8)/(4x1) 8/4=2

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8 0
1 year ago
In Hooke's law, Fspring=kΔx, what does the ∆x stand for
monitta

Answer:

Change in Displacement

Explanation:

delta/triangle = change

x = displacement

formula (if needed): final x - initial x

7 0
2 years ago
A frictionless piston-cylinder device contains 10 kg of superheated vapor at 550 kPa and 340oC. Steam is then cooled at constant
Alla [95]

Answer:

a) the work (W) done during the process is -2043.25 kJ

b) the work (W) done during the process is -2418.96 kJ

Explanation:

Given the data in the question;

mass of water vapor m = 10 kg

initial pressure P₁ = 550 kPa

Initial temperature T₁ = 340 °C

steam cooled at constant pressure until 60 percent of it, by mass, condenses; x = 100% - 60% = 40% = 0.4

from superheated steam table

specific volume v₁ = 0.5092 m³/kg

so the properties of steam at p₂ = 550 kPa, and dryness fraction

x = 0.4

specific volume v₂ = v_f + xv_{fg

v₂ = 0.001097 + 0.4( 0.34261 - 0.001097 )

v₂ = 0.1377 m³/kg

Now, work done during the process;

W = mP₁( v₂ - v₁ )

W = 10 × 550( 0.1377 - 0.5092 )

W = 5500 × -0.3715

W = -2043.25 kJ

Therefore, the work (W) done during the process is -2043.25 kJ

( The negative, indicates work is done on the system )

b)

What would the work done be if steam were cooled at constant pressure until 80 percent of it, by mass, condenses

x₂ = 100% - 80% = 20% = 0.2

specific volume v₂ = v_f + x₂v_{fg

v₂ = 0.001097 + 0.2( 0.34261 - 0.001097 )

v₂ = 0.06939 m³/kg

Now, work done during the process will be;

W = mP₁( v₂ - v₁ )

W = 10 × 550( 0.06939 - 0.5092 )

W = 5500 × -0.43981

W = -2418.96 kJ

Therefore, the work (W) done during the process is -2418.96 kJ

3 0
3 years ago
Individual pyrrole molecules readily join together into larger molecules called polypyrroles. If polypyrroles form from pyrrole
konstantin123 [22]
<h2>Hey there!</h2>

<h2>I guess the correct option is:</h2>

<h3>"(A) Polypyrroles had already formed on or in the zeolite before it was submerged."</h3>

<h2>Hope it help you</h2>
4 0
2 years ago
Explain why the lightbulb is not lit when the switch is in the position shown.
juin [17]
Because the switch isn’t connected to the wire, so the electric charges that is going through the wire isn’t reaching both sockets for the lightbulb.
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3 years ago
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