Answer:
64.1°
Explanation:
Coefficient of friction = Horizontally resolved pushing force divided by Moving force
Coefficient of friction is 0.437
Resolving pushing force to horizontal = Moving force * Cos ∅
Therefore, 0.437 = Cos ∅
and ∅ = Arch Cos 0.437 = 64.1°
Hey there, Your answer wold be 1.36 newtons rounded to 1.4 newton. This is how!
force = k (q1 * q2) / r^2
<span>= (9.0 × 10^9 Nm^2/C^2) [(7.1 × 10^-6 C) (6.9 × 10^-6 C)] / (5.7 × 10^-1 m)^2
</span>
<span>= [ 9.0 × 7.1 × 6.9 / (5.7)^2 ] × 10^-1 N
</span>
<span>= 13.6 × 10^-1 N
</span>
<span>= 1.36 N
</span>
ANSWER-1.4
HOPE I HELPED!!!!!!!!!!
Answer:
the linear speed of the car is 28.83 m/s
Explanation:
Given;
radius of the car, r = 0.33 m
angular speed of each tire, ω = 13.9 rev/s = 13.9 x 2π = 87.35 rad/s
The linear speed of the car is calculated as;
V = ωr
V = 87.35 rad/s x 0.33 m
V = 28.83 m/s
Therefore, the linear speed of the car is 28.83 m/s
Answer:
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