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Fittoniya [83]
3 years ago
7

If the 50.0 kg boy were in a spacecraft 5r from the center of the earth, what would his weight be? (use the 50.0 kg boy for sign

ificant figures)
Physics
2 answers:
jeka57 [31]3 years ago
5 0

The boy weighs 50.0 kg when he is 1R from the center of the Earth. To get his weight  5R away, we can use the formula:

W_{boy} = G * m1 * m2 / r^{2}

Where G, m1, and m2 are constants. By ratio and proportion:

W_{boy}  * ((5R)^{2}= 50.0 kg * 9.81 m/ * ((1R)^{2}

Canceling R on both sides and by computation:

W_{boy}= 19.6 N

Oduvanchick [21]3 years ago
3 0

Answer:

19.6 N

Explanation:

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Answer

given,

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speed of underneath wings = 234 m/s

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density of air =  1.29 kg/m³

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 \Delta P =\dfrac{1}{2}\rho (v_2^2-v_1^2)

 \Delta P =\dfrac{1}{2}\times 1.29\times (265^2-234^2)

 \Delta P =9977.5 Pa

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Displacement vectors of 4 km north, 2km south, 5 km north, and 5km south combine to a total displacement of A 2 km south B 16 km
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In which condition the acceleration of a moving vehicle become zero​
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When,the vehicle has uniform velocity, it's acceleration becomes zero

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The centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².

                     

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