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ioda
3 years ago
5

My dog Ubu can run at 21 mi/h. How far can he travel in 40 minutes?

Physics
1 answer:
Anna007 [38]3 years ago
4 0

Answer:

14

Explanation:

21miles/3=7

7*2=14

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What is the speed of a car that traveled 500 meter in 30 seconds?
GenaCL600 [577]
<h2>Greetings!</h2>

To find speed, you need to remember the formula:

Speed = distance ÷ time

So plug the given values in:

500 ÷ 30 = 16.66

<h3>So the speed is 16.66m/s (metres per second)</h3>
<h2>Hope this helps!</h2>
3 0
3 years ago
What is the momentum of a vehicle that has a mass of 800 kg and is moving at a velocity of 5 m/s
yarga [219]

Answer:

4000 kg.m/s

Explanation:

p=mv

m=800 kg

v=5 m/s

p=(800)(5)= 4000 kg.m/s

3 0
3 years ago
What patterns are caused by the Earth, Sun, and Moon systems?
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3 years ago
Read 2 more answers
Question#7:a) A television uses 1500J of electric energy to produce 1100J 1 point
Vesnalui [34]

Answer:

a.73.3%

b.26.6%

Explanation:

a. The efficiency is the energy output, divided by the energy input, and expressed as a percentage.

#Given the energy input as 1500J and the subsequent output as 1100J, the TV's efficiency is calculated as:

<em />\eta=\frac{E_o}{E_i}\\\\=\frac{1100}{1500}\times 100\%\\\\=73.33\%<em />

Hence, the TV has an efficiency of 33.3%

b. From a above, we know that the TV has an output of 1100J and input of 1500J.

-We therefore calculate it's wastage as the difference between output and input:

<em>Wastage=Energy Input-Energy Output=1500J-1400J=400J</em>

<em />E_w=\frac{E_{wasted}}{E_i}\times 100\%\\\\=(400/1500)\times100\%\\\\=26.67\%<em />

Hence, the TV has wasted of 26.6%

4 0
3 years ago
Two identical blocks are attached to the same massless rope, which is strung around two massless, frictionless pulleys. A massle
Alik [6]

Answer:

The value of mass 1, m1= 6/5m

The value of mass 2, m2= 3/5m

Explanation:

case 1:

here tension and the acceleration will be:

for m1;

  • mg-T=ma
  • 2mg - 2T = 2ma  .....1.

for m2:

  • 2T-mg = ma/2 ..... 2.

adding the both equations,

2mg - 2T + 2T-mg = 2ma + ma/2

a = 2/5 g

putting the value of a into the equation 1.

mg - T = m* (2/5)g

T = 3/5 ( mg )

now

case 2:

The two identical blocks are released from the rest, the tension remains the same as the case 1.

so,

for m1:

  • 2T-m2g=0

for m2:

  • 2m2g - 2T =0

adding both equations we get,

2T-m2g + 2m2g - 2T = 0

m2 = m1 / 2

T = m1*g / 2

here we know that

T (case1) = T (case2)

3/5 ( mg ) = m1*g / 2

m1 = 6/5 m

hence

m2 = 3/5 m

learn more about tension here:

<u>brainly.com/question/23590078</u>

<u />

#SPJ4

4 0
2 years ago
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