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3 years ago

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You hit a golf ball 30.0 m to the south and overshoot the hole. You then hit the ball another 5.0 m back to the north. What is t

he ball's displacement?
m

2 answers:

rewona [7]3 years ago

4 0

25 meters because 30-5=25

Snowcat [4.5K]3 years ago

4 0

The answer is 25 m South! If you hit the ball south 30 m, then the direction of the ball would be south. If you hit the ball again 5 m north, the ball will still be south of you.

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While Bob is demonstrating the gravitational force on falling objects to his class, he drops an 1.0 lb bag of feathers from the

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As per the question Bob drops the bag full with feathers from the top of the building.

The mass of the bag(m)= 1.0 lb

Let the air resistance is neglected.As the bag is under free fall ,hence the only force that acts on the bag is the force of gravity which is in vertical downward direction.

Here the acceleration produced on bag due to the free fall will be nothing else except the acceleration due to gravity i.e g =9.8 m/s^2

Here we are asked to calculate the distance travelled by the bag at the instant 1.5 s

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Hence the correct option is B.

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If a charge at 60c flow in a conductor for 30 second then the current that flow in a conductor is

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Explanation:

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Mass and weight are very different concepts.

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On the other hand, weight is a measure of the gravitational force acting on an object and is directly proportional to the product of the mass $m$ of the body by the acceleration of gravity $g$ :

$W=m.g$

Then, since the Earth and the Moon have different values of gravity, t<u>he weight of an object in each place will vary</u>, but its mass will not.

<h2>Answer 2: b. Force changes by 2/9</h2>

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$F=G\frac{m_{1}m_{2}}{r^2}$ (1)

Where:

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$G$ is the universal gravitation constant

$m_{1}$ and $m_{2}$ are the masses of both bodies.

$r$ is the distance between both bodies

If we double the mass of one object (for example $2m_{1}$ ) and triple the distance between both (for example $3r$ ). The equation (1) will be rewritten as:

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If we compare (1) and (2) we will be able to see the force changes by 2/9.

<h2>Answer 3: b. movement</h2>

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$W=(F)(d)$

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$K=\frac{1}{2}mV^{2}$ (4)

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$K_{2}=\frac{1}{2}(111.197kg)(26.8224m/s)^{2}$ (10)

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<h2>Answer 5: c. the soil will be 5°C</h2>

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$Q=m. c. \Delta T$ (12)

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Answer:

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