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frozen [14]
3 years ago
15

How much data can a digital wave send. (The maximum data)

Physics
1 answer:
Leokris [45]3 years ago
3 0
... A digital signal sent over a telephone connection is
limited to about 60,000 bits (7,500 Bytes) per second. 

... Data sent over "Category 5" and "Category 6" Ethernet cables
usually runs at either 100 megabits or 1 gigabit per second. 

... Data sent over wideband microwave radio signals
is currently capable of up to 1 gigabit (1000 megabits)
per second.

... Fiber optic systems typically operate at 10 gigabits or
40 gigabits per second, but much higher rates have been
accomplished.

<span><span>In 2010, Nippon Telegraph and Telephone Corporation (of Japan)
transferred 69,100 gigabits per second (69.1 Terabits) over a single
fiber that was about 150 miles long.

In 2012, the same company </span><span>transferred 1 million gigabits per second
(1 petabit) over a single fiber about 31 miles long.
__________________________________

1 megabit  =  1 million bits

1 gigabit = 1 billion bits = 1,000 megabits

1 Terabit = 1,000 gigabits = 1 million megabits

1 petabit = 1,000 Terabits = 1 million gigabits = 1 billion megabits

               = 1 billion million bits .</span></span>
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Consider the following neutral electron configurations in which n has a constant value. Which configuration would belong to the
grandymaker [24]

Answer:

he configuration with the highest electronic affinity is 2s2 2p5

Explanation:

Electronic affinity is the variation of energy when we add an electron to a neutral atom to form an ion

When an electron is added, it must occupy a space is the sub-level of the atom, giving more stability when it approaches the configuration of a complete shell with eight electrons (noble gas), so the affinity must increase when moving in a period Group VIII noble gases)

Let's examine the given settings

In this case, when adding an electron, 2s2 is very far from a complete level configuration, so its affinity must be small.

2s2 2p2 when adding an electro the one has a little more affinity, but is still a long way from a full shell, it would be missing 3 electrons

2s2 2sp5 this is the atom with the highest electronic affinity, since i = that when adding an electron the ion has the configuration of a noble gas. This is the most stable on the list

2s2 2p6 already has a full shell making it very difficult to insert an electron into this atom.

In summary, the configuration with the highest electronic affinity is 2s2 2p5

3 0
3 years ago
Read 2 more answers
A primary succession does not include any invasive species <br><br> True or false
yan [13]
To be referenced, it would be true
7 0
4 years ago
The temperature of an air parcel and the kinetic energy of an air parcel are ___________ related. this means that as the tempera
torisob [31]

The temperature of an air parcel and the kinetic energy of an air parcel are directly related. this means that as the temperature of the air parcel increases, the kinetic energy increases.

<h3>What is temperature?</h3>

Temperature is the measure of degree of hotness or coldness of a body.

Temperature is also the measure of the average kinetic energy of a system.

When the heat is applied to body, its temperature increases as the body gains heat.

Thus, the temperature of an air parcel and the kinetic energy of an air parcel are directly related. this means that as the temperature of the air parcel increases, the kinetic energy increases.

Learn more about temperature here: brainly.com/question/25677592

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8 0
2 years ago
The position-time graph of an object is found to be a straight line passing through the origin. What information about the motio
Nostrana [21]
-- The object either left or crossed the starting line exactly at time=0 .

-- The object has been traveling at constant speed for all time that
    we know about.
5 0
3 years ago
8. How did the measured angular magnification of the telescope compare with the theoretical prediction?
Genrish500 [490]

Complete Question

The complete question is shown on the first uploaded image  

Answer:

The theoretical angular magnification lies within the angular magnification range

Explanation:

From the question we are told that

   The  focal length of  B  is  f_{objective } =  43.0 \ cm

    The focal length of  A  is   f_{eye} =  10.4 \  cm

The  theoretical angular  magnification is mathematically represented as

           m = \frac{f_{objective }}{f_{eye}}  =  \frac{43.0}{10.4}

            m = \frac{f_{objective }}{f_{eye}}  =  4.175

Form the question the measured angular magnification ranges from 4 -5

So from the value calculated and the value given we can deduce that the theoretical angular  magnification lies within the angular magnification range

3 0
3 years ago
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