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elena-14-01-66 [18.8K]
4 years ago
10

Plz help =)

Physics
1 answer:
iVinArrow [24]4 years ago
8 0
The correct answer should be 0.03
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A 4.15-volt battery is connected across a parallel-plate capacitor. Illuminating the plates with ultraviolet light causes electr
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Answer:

a ) 2.13 X 10⁶ m/s .

b ) 1.28 X 10⁶ m/s

Explanation:

When electrons are repelled by negative plates and attracted by positive plates , it will increase their kinetic energy.

Increase in their energy = 4.15 eV

= 4.5 X 1.6 X 10⁻¹⁹ J

= 6.64 x 10⁻¹⁹ J

Initial kinetic energy

= 1/2 mv²

= 1/2 x 9.1 x 10⁻³¹ x ( 1.76 x 10⁶)²

= 14.09 X 10⁻¹⁹ J

Total energy

= 6.64 x 10⁻¹⁹+14.09 X 10⁻¹⁹

= 20.73 x 10⁻¹⁹

If V be the increased velocity

1/2 m V² = 20.73 X 10⁻¹⁹

.5 X 9.1 X 10⁻³¹ V² = 20.73 X 10⁻¹⁹

V = 2.13 X 10⁶ m/s .

b ) When electrons are released from positive plate , their speed are reduced because of attraction between electrons and positively charge plates.

Initial kinetic energy

= 14.09 x 10⁻¹⁹ J (see above )

reduction in kinetic energy  

= 6.64 x 10⁻¹⁹ J ( See above )

Total energy with electron -

= 14.09 x 10⁻¹⁹  - 6.64 x 10⁻¹⁹

= 7. 45 x 10⁻¹⁹ J .

If V be the energy of electrons reaching the negative plate,

1/2 m V² =7. 45 x 10⁻¹⁹

V = 1.28 X 10⁶ ms⁻¹

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4 years ago
n general, which trophic level has the LEAST energy available to it? A) producer B) primary consumer C) secondary consumer D) te
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D - tertiary consumer

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A cannon ball fired horizontally from a cliff has a velocity directed at 60 degrees above horizontal when it hits the ground 3.0
Kamila [148]
Since the ball is fired horizontally, the initial y velocity is zero and the time to hit the ground is the same as if the ball was simply dropped from the cliff.  So you can solve the y position function:
-\frac{1}{2}g t^{2}  +  h_{o}=0
giving a height of 44.1m.
The given final velocity vector tells us that the initial x-directed velocity was about 17m/s.
3 0
3 years ago
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Body types can be described as _____ (check all that are correct)Immersive Reader
rewona [7]
Apple, Pear, hourglass, bodybuilder, and rectangle.
4 0
3 years ago
An experiment on the earth's magnetic field is being carried out 1.00 m from an electric cable. What is the maximum allowable cu
Whitepunk [10]

Answer:

The allowed current in the cable is 1.15 A.

Explanation:

Given that,

Distance = 1.00 m

Suppose the magnetic field is 2.3\times10^{-5}\ T and  if the experiment is to be accurate to 1.0 %

We need to calculate the current

Using formula of magnetic field

B=\dfrac{\mu_{0}I}{2\pi r}

I=\dfrac{B\times2\pi r}{\mu_{0}}

Put the value into the formula

I=\dfrac{2.3\times10^{-5}\times2\times\pi\times1.00}{4\pi\times10^{-7}}

I=115\ A

If the experiment is to be accurate to 1.0%

Then,

We need to calculate the allowed current in the cable

I'=(1.0%)\times I

I'=\dfrac{1.0}{100}\times115

I'=1.15\ A

Hence, The allowed current in the cable is 1.15 A.

4 0
3 years ago
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