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4 years ago

Wooden ball lies in a vessel with water so that half of it is immersed in water.

Physics

1 answer:

Ugo [173]4 years ago

5 0

Downward force acting on the ball is 19.6N

Net force acting on the ball is 1960V N

Explanation:

Given:

Mass of the ball, m = 2kg

Density of ball, σ = 800 kg/m³

Density of water, ρ = 1000 kg/m³

Downward force acting by the ball in the vessel = mg

where, g = 9.8m/s²

F = 2 X 9.8

F = 19.6N

Net force acting on the ball:

Fnet = (ρ - σ) Vg

where,

V is the volume of water

Fnet = (1000 - 800) V X 9.8

Fnet = 1960V N

If the volume is known, then substitute the value of V to find the net force.

Thus, Downward force acting on the ball is 19.6N

Net force acting on the ball is 1960V N

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Scientists measure the time between the arrival of an earthquake's __P____ and ___S____ waves to help determine the distance between the recording seismograph and the earthquake epicenter.

Explanation:

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4 years ago

Juanita made an electromagnet by placing an iron bar inside a coil of wire and then running current through the wire. After awhi

swat32

Answer: Correct Ans is B

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3 years ago

A satellite is in a circular orbit about the earth (ME = 5.98 x 10^24 kg). The period of the satellite is 1.26 x 10^4 s. What is

Soloha48 [4]

Answer: $V=5839.051m/s$

Explanation:

According to the Third Kepler’s Law of Planetary motion:

$T^{2}=\frac{4\pi^{2}}{GM}a^{3}$ (1)

Where;:

$T=1.26(10)^{4}s$ is the period of the satellite

$G$ is the Gravitational Constant and its value is $6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$

$M=5.98(10)^{24}kg$ is the mass of the Earth

$a$ is the semimajor axis of the orbit the satllite describes around the Earth (as we know it is a circular orbit, the semimajor axis is equal to the radius of the orbit).

On the other hand, the orbital velocity $V$ is given by:

$V=\sqrt{\frac{GM}{a}}$ (2)

Now, from (1) we can find $a$ , in order to substitute this value in (2):

$a=\sqrt[3]{\frac{T^{2}GM}{4\pi}^{2}}$ (3)

$a=\sqrt[3]{\frac{(1.26(10)^{4}s)^{2}(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.98(10)^{24}kg)}{4\pi}^{2}}$ (4)

$a=11705845.57m$ (5)

Substituting (5) in (2):

$V=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.98(10)^{24}kg)}{11705845.57m}}$ (6)

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3 years ago

At takeoff, a commercial jet has a speed of 72 m/s. Its tires have a diameter of 0.89 m. Part (a) At how many rev/min are the ti

34kurt

Answer:

a) Revolutions per minute = 2.33

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Explanation:

a) Angular velocity is the ratio of linear velocity and radius.

Here linear velocity = 72 m/s

Radius, r = 0.89 x 0. 5 = 0.445 m

Angular velocity

$\omega =\frac{72}{0.445}=161.8rad/s$

Frequency

$f=\frac{2\pi}{\omega}=\frac{2\times \pi}{161.8}=0.0388rev/s=2.33rev/min$

Revolutions per minute = 2.33

b) Centripetal acceleration

$a=\frac{v^2}{r}$

Here linear velocity = 72 m/s

Radius, r = 0.445 m

Substituting

$a=\frac{72^2}{0.445}=11649.44m/s^2$

Centripetal acceleration = 11649.44m/s²

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3 years ago

What is the difference between Weight and Mass? Please give a fair amount of detail!

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The mass of an object is a measure of how much stuff it's made of. So it's
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I think that sums it up fairly well.

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3 years ago

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