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anygoal [31]
3 years ago
5

What is the name of the line drawn perpendicular to the surface where a light ray strikes?

Physics
1 answer:
AnnyKZ [126]3 years ago
7 0
It is the normal line
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A rocket burns fuel to create hot gases that explode violently out of the rocket engine. This explosion creates thrust. Thrust i
Lerok [7]

Answer:

Thrust due to fuel consumption must overcome gravitational force from the Earth to send the rocket up into space.

Explanation:

From the concept of Escape Velocity, derived from Newton's Law of Gravitation, definition of Work, Work-Energy Theorem and Principle of Energy Conservation, which is the minimum speed such that rocket can overcome gravitational forces exerted by the Earth, and according to the Tsiolkovski's Rocket Equation, which states that thrust done by the rocket is equal to the change in linear momentum of the rocket itself, we conclude that thrust due to fuel consumption must overcome gravitational force from the Earth to send the rocket up into space.

5 0
3 years ago
FIND THE WEIGHT OF A 80 KG MAN ON THE SURFACE OF MOON? WHAT SHOULD BE HISS MASS ON THE EARTH AND ON THE MOON? (ge = 9.8 m/s2 ; g
elena55 [62]

Weight = (mass) x (acceleration of gravity at the place where the mass is) .

Man's mass = 80 kg

His weight on Earth = (80 kg) x (9.8 m/s²) = 784 newtons (about 176 pounds)

His weight on the Moon = (80 kg) x (1.63 m/s²) = <em>130.4 newtons</em> (about  29.2 pounds)

His mass is <em>80 kg</em>.  Mass is the thing about him that doesn't change. 
He has the same mass on the Earth, on the Moon, or anywhere.

8 0
3 years ago
Which object will NOT allow an electric current to flow through it?
galben [10]

Answer: C. A rubber eraser

6 0
3 years ago
When the velocity of a body increase with time, it's acceleration is ---------
BabaBlast [244]

Answer:

Negative

Explanation:

4 0
3 years ago
A spring with k = 19.5 N/cm is initially stretched 1.39 cm from its equilibrium length. a) How much more energy is needed to fur
lara31 [8.8K]

Answer:

Energy needed = 54.02 J

Explanation:

the Energy in an elastic spring from hookes law is given  as

F= ke , therefore the energy (E) is

E = \frac{1}{2} Ke^{2}

K = 19.5 N/cm

e = 1.39cm

E = \frac{1}{2} x 19.5 x 1.39

E = 13.55 J

The energy to stretch the spring for 6.93cm is

E = \frac{1}{2} x 19.5 x 6.93

E = 67.57 J

The more energy needed for the further stretch is

67.57 - 13.55

Energy needed = 54.02 J

7 0
3 years ago
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