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Alex787 [66]
3 years ago
6

How many grams of kbr must be dissolved to make 25.0 ml of a solution that has a molarity of 0.85 m?

Chemistry
1 answer:
lyudmila [28]3 years ago
4 0
Molarity is defined as the number of moles of solute in 1 L of solution 
molarity of solution to be prepared is 0.85 M
this means that there should be 0.85 mol of KBr in 1 L of solution 
if 1 L contains - 0.85 mol
then 25.0 mL should contain - 0.85 mol / 1000 mL x 25.0 mL = 0.0213 mol 
mass of KBr - 0.0213 mol x 119 g/mol = 2.53 g
mass of KBr that should be dissolved in 25.0 mL is 2.53 g

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Write a balanced net ionic equation for the following reaction. Explain how you arrived at this answer. What did you cancel out?
Alex787 [66]

 The net ionic equation  is

Ag⁺(aq)  +Cl⁻(aq) →  AgCl(s)

<u><em>Explanation</em></u>

AgNO₃ (aq)  + KCl (aq)→ AgCl(s) +KNO₃(aq)


from above  molecular equation break  all  soluble electrolyte  into ions

Ag⁺(aq) +NO₃⁻ (aq) + K⁺(aq) +Cl⁻(aq) →   AgCl (s) + K⁺(aq) + No₃⁻(aq)


cancel the spectator  ions  in both side  of  equation =K⁺  and NO₃⁻  ions


The net  ionic equation is therefore

= Ag⁺(aq)  + Cl⁻(aq) →    AgCl(s)

4 0
3 years ago
Formaldehyde (h2co) reacts with oxygen to form co2 and h2o. how many moles of co2 will be produced from reacting 2 moles of h2co
bogdanovich [222]
Answer:
            2 mol of CO₂

Solution:

The reaction is as follow,

                              H₂CO  +  O₂     →     CO₂  +  H₂O

According to this equation,

                         1 mole of H₂CO produces  =  1 mole of CO₂
So,
                   2 moles of H₂CO will produce  =  X moles of CO₂

Solving for X,
                      X  =  (2 mol × 1 mol) ÷ 1 mol

                      X  =  2 mol of CO₂
7 0
3 years ago
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The domain Archaea are unicellular prokaryotes and can be autotrophs or heterotrophs
nexus9112 [7]

Answer:

I think its true I dont really know

Explanation:

true

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3 years ago
How is heat produced in a chemical change​
Snezhnost [94]

Answer:Hola UwU

Most chemical reactions involve the breaking and formation of chemical bonds. It takes energy to break a chemical bond but energy is released when chemical bonds are formed. If more energy is released than consumed, then the chemical reaction evolves heat and is said to be exothermic.

Explanation:Adios~ UnU haha

7 0
3 years ago
When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H
Debora [2.8K]

Answer:

Y=58.15\%

Explanation:

Hello,

For the given chemical reaction:

Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol  Al_2S_3

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3

Finally, we compute the percent yield with the obtained 2.10 g:

Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%

Best regards.

7 0
3 years ago
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