I think iron? i’m not 100% sure
Answer:1). Distance of far point x=0.9m
Therefore, since the image is virtual
-f=-x = -0.9m
Power of the concave lenses = 1/f = 1/-0.9
= -1.11D
2 ) near point is 21cm = 0.21m
Power = 4-1/near point
= 4/0.21
= 14.2D.
A table would be the most appropriate because that way you can compare the data.
These are characteristics of a wave. The amplitude is how high and low the waves go. Crests are high points on the wave, and troughs are low points on the wave.
Answer:
= 2.83
Explanation:
F number (N) is given by the formula;
F- number = f/D
where f = focal length of lens and D = diameter of the aperture
Therefore;
F number = 17 cm/6 cm
<u> = 2.83</u>
