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Arturiano [62]
3 years ago
15

Twenty-eight soccer teams are playing a tournament. If each team has 19

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
8 0

Answer:532

Step-by-step explanation:if there are 28 teams you multiply it by 19 you get 532

28 teams

19 players per team

19 multiply by 28 is 532 players total

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Susan worked 5 out of 8 hours during the day what percentage of the day does she work
Aleksandr-060686 [28]
5/8 * 125/125 = 625/1,000 = 0.625
62.5 percent
Solution: 62.5%
4 0
3 years ago
Read 2 more answers
The formula for the surface area of a cylinder is SA= 2 pi r (h + r). What is the surface area of a cylinder when r = 3 centimet
Grace [21]

Answer:

if you google (surface area of a cylinder) it lets you input the radius and height and it gives your answer

Step-by-step explanation:

3 0
3 years ago
If x=5^a, find the value of 5x. How?
Yakvenalex [24]

Answer:

5x = 5^{(a+1)}

Step-by-step explanation:

Here is a problem with the concept of properties of the exponent.

We are given x = 5^{a} and we have to find the value of 5x.

Now, 5x = 5 \times 5^{a} {Since we are given that x = 5^{a}}

⇒ 5x = 5^{1} \times 5^{a} {Since we can write x = x^{1}}

⇒ 5x = 5^{(a+1)} {Since we know the formula of exponent as x^{m} \times x^{n} = x^{(m + n)}}

(Answer)

7 0
3 years ago
A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0
3 years ago
Mr.William orders 2 feet of trim to decorate pillows. If he needs 1inch of trim for each pillow, how many pillows can he decorat
navik [9.2K]

2 feet = 24 inches

24 inches divided by 1 inch = 24

Answer is 24 pillows.

3 0
3 years ago
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