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3 years ago

How do you solve 2i and 2ii

Mathematics

2 answers:

Ivanshal [37]3 years ago

7 0

Given:

Tn = 2n+5

`The fifth term, i.e., n=5

Substituting the value inside the formula we get,

2(5) + 5 => 10 + 5 => 15

2. The Eighth term, i.e., n=8

Substituting the value inside the formula we get,

2(8) + 5 => 16 + 5 => 21

natta225 [31]3 years ago

5 0

Answer:

15 and 21

Step-by-step explanation:

Given the n th term formula

T = 2n + 5

To find the 5 th and 8 th terms substitute n = 5 and n = 8 into the formula

$T_{5}$ = (2 × 5) + 5 = 10 + 5 = 15

$T_{8}$ = (2 × 8) + 5 = 16 + 5 = 21

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16. Tell whether the lines for each pair of equations are parallel, perpendicular, or neither.

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Answer:

Given equation are:

$y = -\frac{1}{4}x+8$ ......[1]

$-2x+8y = 4$ .....[2]

The two lines are parallel lines then their slopes will be equal.

When two lines are perpendicular then, the slope of lines are the negative reciprocals of each other.

Now, Equation of a line is in the form of y =mx+b where m is the slope of the line.

Slope $(m_1)$ of equation of line in [1] is;

$y = -\frac{1}{4}x+8$

then;

$m_1= -\frac{1}{4}$

Slope $(m_2)$ of equation of line in [2];

$-2x+8y = 4$

Add both sides 2x we get;

-2x + 8y + 2x = 2x + 4

Simplify:

8y = 2x +4

Divide both sides by 8 we get;

$y = \frac{1}{4} x + \frac{1}{2}$

then;

$m_2 = \frac{1}{4}$

Therefore, the given two lines are neither parallel nor perpendicular.

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Tinwa has 2 candy and her six friends have two each how many candy do they all have

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Pepsi [2]

Answer:

The height of right circular cone is h = 15.416 cm

Step-by-step explanation:

The formula used to calculate lateral surface area of right circular cone is: $s=\pi r\sqrt{r^2+h^2}$

where r is radius and h is height.

We are given:

Lateral surface area s = 236.64 cm²

Radius r = 4.75 cm

We need to find height of right circular cone.

Putting values in the formula and finding height:

$s=\pi r\sqrt{r^2+h^2}\\236.64=3.14(4.75)\sqrt{(3.75)^2+h^2} \\236.64=14.915\sqrt{(3.75)^2+h^2} \\\frac{236.64}{14.915}=\sqrt{14.0625+h^2} \\15.866=\sqrt{14.0625+h^2} \\Switching\:sides\:\\\sqrt{14.0625+h^2} =15.866\\Taking\:square\:on\:both\:sides\\(\sqrt{14.0625+h^2})^2 =(15.866)^2\\14.0625+h^2=251.729\\h^2=251.729-14.0625\\h^2=237.6665\\Taking\:square\:root\:on\:both\:sides\\\sqrt{h^2}=\sqrt{237.6665} \\h=15.416$