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deff fn [24]
3 years ago
5

How do you solve 2i and 2ii​

Mathematics
2 answers:
Ivanshal [37]3 years ago
7 0

Given:

Tn = 2n+5

  1. `The fifth term, i.e., n=5

Substituting the value inside the formula we get,

2(5) + 5 => 10 + 5 => 15

   2.  The Eighth term, i.e., n=8

Substituting the value inside the formula we get,

2(8) + 5 => 16 + 5 => 21

natta225 [31]3 years ago
5 0

Answer:

15 and 21

Step-by-step explanation:

Given the n th term formula

T = 2n + 5

To find the 5 th and 8 th terms substitute n = 5 and n = 8 into the formula

T_{5} = (2 × 5) + 5 = 10 + 5 = 15

T_{8} = (2 × 8) + 5 = 16 + 5 = 21

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Answer: y^4 + \frac{-73}{35}y^2- 2

Step-by-step explanation:

Use FOIL:

y^4 + \frac{-14}{5}y^2 + \frac{5}{7}y^2 + \frac{-70}{35}

Make  \frac{-14}{5}y^2 and \frac{5}{7}y^2 have the same numerator:

\frac{-14*7}{5*7}y^2 =\frac{-98}{35}y^2

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Then add like terms and simplify:

y^4 + \frac{-98}{35}y^2 + \frac{25}{35} y^2 + \frac{-70}{35}

y^4 + \frac{-73}{35}y^2- 2

7 0
3 years ago
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