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4 years ago

How do you solve 2i and 2ii

Mathematics

2 answers:

Ivanshal [37]4 years ago

7 0

Given:

Tn = 2n+5

`The fifth term, i.e., n=5

Substituting the value inside the formula we get,

2(5) + 5 => 10 + 5 => 15

2. The Eighth term, i.e., n=8

Substituting the value inside the formula we get,

2(8) + 5 => 16 + 5 => 21

natta225 [31]4 years ago

5 0

Answer:

15 and 21

Step-by-step explanation:

Given the n th term formula

T = 2n + 5

To find the 5 th and 8 th terms substitute n = 5 and n = 8 into the formula

$T_{5}$ = (2 × 5) + 5 = 10 + 5 = 15

$T_{8}$ = (2 × 8) + 5 = 16 + 5 = 21

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Answer:

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3 years ago

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Julli [10]

Answer:

B. and C.

Step-by-step explanation:

1. Set the polynomial equal to zero:

x² + 5x + 7 = 0

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3. Solve the square root:

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Thus, options B and C are the answers.

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2 years ago

If the equation y = 15x + 2 is changed to y = 15x - 4, how will the graph of the line change?

igomit [66]

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3 years ago

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1/4+3/8 and show work, please!!

gregori [183]

Answer:

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Step-by-step explanation:

Step 1 : Convert both fractions so they have the same denominator (bottom number in the fraction.)

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