Which attributes does the exosphere have?

How does the electron-cloud model describe electrons?

Dominik [7]

Answer:

Yo, you just kind of answered it yourself. The Electron Cloud Model is the informal way of describing an atomic orbital.

Explanation:

The analogy of the cloud of electrons is really describing the groups of electrons orbiting around said atom. Depending on the atom, there will be many or few electrons orbiting around it on all sides which can resemble an all-encompassing cloud.

5 0

3 years ago

A car is traveling down the highway cruise control at 50m/s (this means its is traveling with a constant velocity NOT accelerati

lawyer [7]

Given parameters:

Speed of car = 50m/s

Time of travel = 5minutes (300s)

Unknown;

Distance of travel = ?

To solve this problem, we need to understand how speed relates with distance and time.

Speed is a physical quantity. It is the distance traveled divided by time taken.

Speed = $\frac{distance}{time}$

So,

Distance = speed x time

Input the parameters and solve for the distance;

Distance = 50m/s x 300s

Distance = 15000m

The distance covered during this time interval and speed is 15000m

3 0

3 years ago

The 1.19 kg head of a hammer has a speed of 8.4 m/s just before it strikes a nail (Fig. 14-13) and is brought to rest. Estimate

KATRIN_1 [288]

Answer:

The temperature rise is $143.9\ K$ .

Explanation:

Given the mass of the hammer $(m)$ is 1.19 kg.

And the speed of the hammer $(v)$ is 8.4 m/s.

We need to find the temperature change of iron nail having 20 hammer blows.

First, we will find the kinetic energy of the each blow of hammer.

$K.E=\frac{1}{2}mv^2$

$K.E=\frac{1}{2}\times 1.19\times 8.4^2=41.99\ J$

For 20 such blows, the kinetic energy will be

$20\times K.E=20\times 41.99=839.8\ J$

Let us assume that the nail absorbs all the kinetic energy. So, this 839.8 J will be converted into heat energy $(Q)$ .

Now,

$Q=839.8\ J$

Also, we know that

$Q=mc\Delta_T$

Where,

$m$ is the mass of the nail, which is $13\ g=\frac{13}{1000}=0.013\ kg$

$c$ is the specific heat capacity of iron, which is 449 J/kg.K

$\Delta_T$ is the change in temperature.

Plug these value we get,

$Q=mc\Delta_T\\839.8\ J=(0.013\ kg)(449\ J/kg.K)\times\Delta_T\\\Delta_T=\frac{839.8}{0.013\times 449}\\\\\Delta_T=143.9\ K$

We can see the temperature rise is 143.9 K.

4 0

4 years ago

3. Which vehicle has more momentum? *

AysviL [449]

Answer:

the one with v = 25 m/s

Explanation:

Momentum = m * v

if they both have the same mass (15000 kg) , then the one with the higher v has more momentum...I think A= 25 m/s

5 0

2 years ago

Inside the repetitive "loop," assuming that we use the final velocity in each time interval as the approximation to the average

Mumz [18]

Answer:

A. Calculate vector

B. Update vector of each object

C. Update position of each object

Explanation:

Taking assumption of a system in which the forces are a function of the previous step's final position:

Firstly, we calculate the (vector) forces acting on the objects.

Secondly, Update the (vector) momentum of each object

(note: also update the velocity).

Thirdly, Update the (vector) position of each object.

The other operations are as follows;

i. select (dt),

ii. define mass,

iii. Put down constants,

iv. initialize variables, this would occur before the time-step loop is entered.

3 0

4 years ago