The equilibrium constant of the reaction is 1.21 * 10^6 while the change in free energy is -34.7 kJ.
<h3>What is equilirium constant?</h3>
The equilibrium constant shows the extent of conversion of reactants to products.
Now we know from the Nernst equation that;
Ecell = E°cell - 0.0592/n logQ
E°cell = 0.52−0.16=0.36 V
Since Ecell = 0 V at equilibrium,
0 = 0.36 - 0.0592/1 log K
0.36 = 0.0592/1 log K
log K = 0.36/ 0.0592
K = antiog (0.36/ 0.0592)
K = 1.21 * 10^6
ΔG = -RT lnK
ΔG =-(8.314 * 298 * ln1.21 * 10^6)
ΔG =-34.7 kJ
Learn more about equilibrium constant:brainly.com/question/10038290
Answer:
The correct answer is -2878 kJ/mol.
Explanation:
The reaction that takes place at the time of the oxidation of glucose is,
C₆H₁₂O₆ (s) + 6O₂ (g) ⇒ 6CO₂ (g) + 6H₂O (l)
The standard free energy change for the oxidation of glucose can be determined by using the formula,
ΔG°rxn = ∑nΔG°f (products) - ∑nΔG°f (reactants)
The ΔG°f for glucose is -910.56 kJ/mol, for oxygen is 0 kJ/mol, for H2O -237.14 kJ/mol and for CO2 is -394.39 kJ/mol.
Therefore, ΔG°rxn = 6 (-237.14) + 6 (-394.39) - (-910.56)
ΔG°rxn = -2878 kJ/mol
Answer : The % of (+) limonene isomer = 79%
The % of (-) limonene isomer = 0%
The % of enantiomeric excess = 58%
Explanation : Enantiomeric excess (ee) is the measurement of purity used for chiral substances.
Given,
% of pure limonene enantiomer = The % of (+) limonene isomer = 79%
Therefore, The % of (-) limonene isomer = 0%
Formula used :
Where, ee → enantiomeric excess
Now, put all the values in above formula, we get the value of enantiomeric excess (ee).
= 58%
Like mitosis, meiosis is a form of eukaryotic cell division. However, these two processes distribute genetic material among the resulting daughter cells in very different ways. meiosis gives rise to four unique daughter cells, each of which has half the number of chromosomes as the parent cell. Because meiosis creates cells that are destined to become gametes (or reproductive cells), this reduction in chromosome number is critical — without it, the union of two gametes during fertilization would result in offspring with twice the normal number of chromosomes!
