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PtichkaEL [24]
3 years ago
10

You are driving your vehicle through a busy intersection. A vehicle drives across your path. You cannot avoid crashing into the

other vehicle. What type of crash should minimize the severity of the injuries and damage that occur?
Chemistry
2 answers:
garik1379 [7]3 years ago
4 0

Answer:

<em><u>Brace of Impact</u></em>

Explanation:

Various researches have  shown that people who are aware of a collision and brace before the impact have less injury and long term outcomes. So people should brace for impact as when you brace the muscles in your neck can better protect the nerves, discs and ligaments and if you stay relaxed then these ligaments, discs, nerves will take more force and would result in more injury.

SVETLANKA909090 [29]3 years ago
3 0

my teacher call it bb you beep and brace for impact

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5 0
3 years ago
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If the pka of hcho2 is 3.74 and the ph of an hcho2/nacho2 solution is 3.89, it means that
Andrei [34K]

Hi, the question has some missing part. The complete question should be " If the pK_{a} of HCHO_{2} is 3.74 and the pH of an HCHO_{2}/NaCHO_{2} solution is 3.89, it means that -

(a) [HCHO_{2}]=[NaCHO_{2}]

(b) [HCHO_{2}]> [NaCHO_{2}]

(c) [HCHO_{2}]<  [NaCHO_{2}]

Which of the options are true?"

Answer: Option (c) is true.

Explanation:

HCHO_{2}/NaCHO_{2} is an weak acid-conjugate base buffer. Hence, in accordance with Henderson-Hasselbalch equation-

                  pH=pK_{a}(HCHO_{2})+log(\frac{[CHO_{2}^{-}]}{[HCHO_{2}]})

Here, pH = 3.89, pK_{a} of HCHO_{2} = 3.74

So, 3.89=3.74+log(\frac{[CHO_{2}^{-}]}{[HCHO_{2}]})

or, \frac{[CHO_{2}^{-}]}{[HCHO_{2}]} = 1.41 (>1)

So,  [CHO_{2}^{-}]> [HCHO_{2}]

or, [NaCHO_{2}]> [HCHO_{2}]

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6 0
4 years ago
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3 years ago
What is the theoretical yield of aluminum that can be produced by the reaction of 60.0 g of aluminum oxide with 30.0 g of carbon
Varvara68 [4.7K]

Answer: 31.8 g

Explanation:

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\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Al_2O_3=\frac{60.0g}{102g/mol}=0.59moles

\text{Moles of} C=\frac{30.0g}{12g/mol}=2.5moles

Al_2O_3+3C\rightarrow 2Al+3CO  

According to stoichiometry :

1 mole of Al_2O_3 require 3 moles of C

Thus 0.59 moles of Al_2O_3 will require=\frac{3}{1}\times 0.59=1.77moles  of C

Thus Al_2O_3 is the limiting reagent as it limits the formation of product and C is the excess reagent as it is present in more amount than required.

As 1 mole of Al_2O_3 give = 2 moles of Al

Thus 0.59 moles of Al_2O_3 give =\frac{2}{1}\times 0.59=1.18moles  of Al

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5 0
3 years ago
Mendel found that yellow pea pod color (G) was dominant to green pea pod color (g), and that round seeds (W) were dominant to wr
wlad13 [49]

Answer:

100% pea plants will be with green pod and with round seeds.

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6 0
4 years ago
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