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Pavlova-9 [17]
3 years ago
10

15 POINTS!!!

Physics
2 answers:
defon3 years ago
5 0
Hey there!

I believe the answer is conductive.

Hope it helped!
Mariulka [41]3 years ago
5 0
"If you were to microwave a bowl of soup for too long and you burn your hands as you remove the bowl from the microwave, the heat transfer that would be demonstrated would be called: conduction. Conduction occurs when heat from one substance comes in contact in another substance. Just like when heat from the bowl came in contact with your hand. "
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A BALL IS THREWN WITH AN ANGULAR DIRECTION TOTHE HORIZONTAL AXIS .IT TAKES 4SECONDS TO MOVE BETWEEN TWO PILLARA WICH HAS A HEIGH
hjlf

Answer:

So -24.5 m merely means the depth of the base of the tower ie the ground from the top of the tower. So wrt the ground height of the tower = 24.5 m.

Explanation:

6 0
3 years ago
Se suelta un cuerpo desde la azotea de un edificio de 180m de alto. Luego de 3s se lanza verticalmente hacia abajo otro cuerpo.
NARA [144]

Answer:CcCcccccc

Explanation:

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6 0
4 years ago
A parallel-plate capacitor is connected to a battery. The space between the two plates is empty. If the separation between the c
Maru [420]

Answer:

The final stored energy will become half.

Explanation:

 We know that stored energy in the capacitor is given as

E=\dfrac{1}{2}CV^2

C=capacitance

V=Voltage difference

E=Energy

C=\dfrac{\varepsilon A}{d}

d=Distance between plates

A=Area

E=\dfrac{1}{2}\times \dfrac{\varepsilon A}{d}\times V^2

If the distance between plates get double ,say d' = 2 d

Then stored energy

E'=\dfrac{1}{2}\times \dfrac{\varepsilon A}{d'}\times V^2

E'=\dfrac{1}{2}\times \dfrac{\varepsilon A}{2d}\times V^2

E'=\dfrac {E}{2}

Therefore the final stored energy will become half.

5 0
4 years ago
Plzzzz urgent <br><br><br>solve this​
Mariana [72]

Answer:

\large{ \tt{☄ \: EXPLANATION}} :

  • Before solving , You'll have to know - When an object starts from the state of rest , in this case , initial velocity ( u ) = 0

  • Notice that we're provided the time ( t ) in minutes. So , first thing we have to do is convert the minutes into seconds. It would be - Time ( t ) = 5 minutes = 5 × 60 sec = 300 sec [ 1 min = 60 sec ]

  • Here , We're provided - Initial velocity ( u ) = 0 , Final velocity ( v ) = 60 m / s , Time taken ( t ) = 300 seconds & We're asked to find out the acceleration ( a ) & distance covered by the jeep ( s ) .

\large{ \tt{♨ \:LET'S \: START}} :

  • Acceleration is defined as the rate of change of velocity. We know :

\large{ \boxed{ \tt{❁ \: ACCELERATION \: (a) =  \frac{FINAL \: VELOCITY(v) - INITIAL \: VELOCITY(u)}{TIME \: TAKEN \: ( \: t \: )}}}}

- Plug the values & then simplify !

\large{ \bf{↬a =  \frac{60 - 0}{300}  =  \frac{60}{300} =  \boxed{ \bold{ \bf{0.2 \: m {s}^{ - 2} }}} }}

  • The acceleration of the jeep is 0.2 m/s²

\large{ \tt{۵ \: AGAIN, \: USING\: SECOND \: EQUATION \: OF \: MOTION}} :

\boxed{ \large{ \bf{✾ \: s =  \frac{u + v}{2}  \times t}}}

- Plug the values & then simplify !

\large{ \bf{↦s =  \frac{0 + 60}{2}  \times 300 =  \boxed{ \bold{ \bf{9000 \: m}}}}}

  • The distance covered by the jeep is 9000 m .

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7 0
3 years ago
"A short-wave radio antenna is supported by two guy wires, 150 ft and 170 ft long. Each wire is attached to the top of the anten
Nonamiya [84]

Answer:

The anchor points are 78.37 ft and 111.99 ft

Explanation:

If you look at the attached (Fig 1) you will find that the union of antenna and its guy wires forms two right triangles. To solve problems that involve this kind of triangles, you can apply trigonometric functions (sine, cosine, etc) and Pythagoras Theorem. Trigonometric functions states the relation between angles, sides and hypotenuse of a right triangle. If you look Fig2, considering α angle, "b" is the opposite side, "a" the adjacent side and "c" the hypotenuse. Then

a) Sine (α) = b/c it means opposite side/hypotenuse

b) Cosine (α)= a/c, it means adjacent side/hypotenuse

c) Tangent (α) = b/a opposite side/adjacent side.

Pythagoras theorem states that if you called "a" and "b", the sides of the right triangle, and "c" the hypotenuse, then:

                                      a² + b² = c²    

As the problem states the lengths 150 ft and 170 ft represents the value of the hypotenuse of each triangle and 65° is one of the angles of the triangle with 150 ft hypotenuse. So you can solve this using sin (65°) to find the height of the antenna (h) and then the two distances (x and y,).

Sine (65°) = h/ 150 ft ⇒ Sine (65°) x 150ft = h ⇒ h = 127.9 ft.

To find x : Cosine (65°) = x/ 150 ft ⇒ Cosine (65°) x 150 ft = x

⇒ x = 78.37 ft.

And finally, to find y we can apply Pythagoras theorem

(170 ft)² = (127.9 ft)² + y² ⇒ y² = (170 ft)² - (127.9 ft)² ⇒ y = 111.99 ft

Summarizing, the anchor points are 78.37 ft and 111.99 ft

4 0
3 years ago
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