3 years ago

What is the ultimate energy source for most wind?

Physics

2 answers:

Varvara68 [4.7K]3 years ago

6 0

Answer:

solar radiation

Explanation:

Vinvika [58]3 years ago

5 0

The ultimate energy source for wind comes from Earth's uneven heating on Earth's surface which can be caused mainly by the sun.

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Explain why the drill bit gets hot when it's turning in the wood

alexgriva [62]

The friction between the two objects creates heat.

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3 years ago

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a bicyclist travels with an averahe velocity of 15km/h north, for 20 minutes .what is his displacement ?

Lunna [17]

Explanation:

velocity = 15 km/hr = 15×1000m / 60×60s

= 4.17 m/s

time= 20 min= 20 × 60s

= 1200s

displacement =?

we know that,

V = D / t

or, 4.17 = D / 1200

or, D = 4.17 × 1200

or,D = 5004 m

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2 years ago

Un tren va a una velocidad de 18m/s frena y se detiene en 15s calcula su aceleracion y la distancia recorrida al frenar

Rudiy27

Answer:

Acceleration is -1.2 m/s² and distance covered is 135 m.

Explanation:

A train going at a speed of 18m / s brakes and stops in 15s calculates its acceleration and the distance traveled when braking

Given that,

The initial speed of the train, u = 18 m/s

Final speed, v = 0

Time, t = 15 s

We need to find acceleration and distance traveled when braking. Let a is acceleration and distance traveled.

Acceleration,

$a=\dfrac{v-u}{t}\\\\a=\dfrac{0-18}{15}\\\\a=-1.2\ m/s^2$

Using third equation of motion,

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-18^2}{2\times (-1.2)}\\\\d=135\ m$

Hence, acceleration is -1.2 m/s² and distance covered is 135 m.

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3 years ago

What could you do to increase the electric potential energy between two positively charged particles by a factor of 16?

ivann1987 [24]

$Electric~potential ~energy~U_{E}=K_{e}.\dfrac{Qq}{R}\\so~ U_{E} \propto \dfrac{1}{R}$
so to increase Ue by 16 times you gotta reduce R(distence) by 16 times

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3 years ago

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The acceleration of a particle is given by a = -kt^2, where a is in meters per second squared and the time t is in seconds. If t

QveST [7]

Answer:

Velocity is zero.

Explanation:

Given:

acceleration of particle, $a=-k.t^2\ m.s^{-2}$

time of observation, $t=0\ s$

We know that acceleration is defined as the rate of change in velocity and hence we integrate the expression of acceleration.

<u>Now the velocity can be given as:</u>

$v=\int\limits {a} .\, dt=-k.\frac{t^3}{3}$

Put t = 0 we get:

$v=0\ m.s^{-1}$

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3 years ago