The amount of air resistance<span> an </span>object<span> experiences depends on its speed, its cross-sectional area, its shape and the density of the </span>air<span>. </span>Air<span> densities vary with altitude, temperature and humidity. Nonetheless, 1.29 kg/m</span>3<span> is a very reasonable value. The shape of an </span>object affects<span> the drag coefficient (C</span>d<span>)</span>
To solve the problem it is necessary to identify the equation in the manner given above.
This equation corresponds to the displacement of a body under the principle of simple harmonic movement.
Where,

PART A) Our equation corresponds to

Therefore the value of omega is equivalent to that of

From the definition we know that the period as a function of angular velocity is equivalent to



This same point is the equivalent of the maximum point of the speed that the body can reach, since the internal expression of the
Is equivalent to . So the maximum speed that the body can reach is,



Therefore the maximum felocity will be 5ft / s
PART B) The period of graph is the time taken to reach from one maximum point to next point maximum point, then


Answer:
0.33 Amp
8 Watts
Explanation:
The current through the 12 Ω resistor will be given by Ohm's law:
4 V / 12 Ω = 1/3 Amp ≈ 0.33 Amp
The power dissipated on the 2 Ω resistor can be calculated via the formula:
which gives:
4^2 / 2 = 8 Watts
2. Newton's laws of motion