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4 years ago

What is the percent by mass of 54.7g of calcium chloride dissolved in 500g of water?

1 answer:

3 0

% by mass = (mass solute/mass solution)*100%
mass of the solute = 54.7 g
mass of the solution = mass solute + mass solvent=54.7+500=554.7 g
% by mass = (54.7/554.7)*100%≈0.0986*100% = 9.86%

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Iron and vanadium both have the BCC crystal structure and V forms a substitutional solid solution for concentrations up to appro

Hatshy [7]

Answer:

The unit cell edge length for the alloy is 0.288 nm

Explanation:

Given;

concentration of vanadium, Cv = 8 wt%

concentration of iron, Cfe = 92 wt%

density of vanadium = 6.11 g/cm³

density of iron = 7.86 g/cm³

atomic weight of vanadium, Av = 50.94 g/mol

atomic weight of iron, Afe= 55.85 g/mol

Step 1: determine the average density of the alloy

$\rho _{Avg.} = \frac{100}{\frac{C_v}{\rho _v} + \frac{C__{Fe}}{\rho _{Fe}} }$

$\rho _{Avg.} = \frac{100}{\frac{8}{6.11} + \frac{92}{7.86} } = 7.68 \ g/cm^3$

Step 2: determine the average atomic weight of the alloy

$A _{Avg.} = \frac{100}{\frac{C_v}{A _v} + \frac{C__{Fe}}{A _{Fe}} }$

$A _{Avg.} = \frac{100}{\frac{8}{50.94} + \frac{92}{55.85} } = 55.42 \ g/mole$

Step 3: determine unit cell volume

$V_c=\frac{nA_{avg.}}{\rho _{avg.} N_a}$

for a BCC crystal structure, there are 2 atoms per unit cell; n = 2

$V_c=\frac{2*55.42}{ 7.68*6.022*10^{23}} = 2.397*10^{-23} \ cm^3/cell$

Step 4: determine the unit cell edge length

Vc = a³

$a = V_c{^\frac{1}{3} }\\\\a = (2.397*10^{-23}}){^\frac{1}{3}}\\\\a = 2.88 *10^{-8} \ cm$ = 0.288 nm

Therefore, the unit cell edge length for the alloy is 0.288 nm

4 0

4 years ago

Calculate the pressure (in kpa) of 1.5 mole of helium gas at 354 k when it occupies a volume of 16.5l.

3241004551 [841]

Answer:

267.57 kPa

Explanation:

Ideal gas law:

PV = n RT R = 8.314462 L-kPa/K-mol

P (16.5) = 1.5 (8.314462)(354) P = 267.57 kPa

8 0

2 years ago

Chemistry. Will mark Brainly.

kogti [31]

Answer:

c is right

Explanation:

8 0

3 years ago

A sample of methane (CH4) has a volume of 25 mL at a pressure of 0.80 atm. What is the volume of the gas at each of the followin

Xelga [282]

Answer:

a. 50ml b.10ml c. 6.097ml d. 190.1 ml

Explanation:

According to Boyle's law

Volume is inversely proportional to pressure at constant temerature

Mathematically

P1V1=P2V2

P1=Initial pressure=0.8atm

V1=Initial volume=25ml

making V2 the subject

at 0.4atm P2=0.4 atm,

V2=25×0.8/0.4

=50ml

at 2 atm V2=25×0.8/2

=10 ml

1mmHg=0.00131579

2500mmHg=3.28 atm

At 3.28 atm,V2=25×0.8/3.28

=6.097 ml

at 80.0 torr

1 torr=0.00131579

80 torr=0.1052 atm

at 0.1048 atm V2=25×0.8/0.1048

=190.1 ml

4 0

3 years ago

How many grams of carbon dioxide are in 35.6 liters of co2

lina2011 [118]

The grams of carbon dioxide that are in 35.6 liters of Co2 is calculates as below
calculate the number of moles of CO2

At STP 1 mole = 22.4 L

what about 35.6 liters

= 1mole x 35.6 liters/ 22.4 liters = 1.589 moles

mass of CO2 = moles x molar mass of CO2

= 1.589 mol x 44 g/mol = 69.92 grams

3 0

3 years ago