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damaskus [11]
3 years ago
11

What type of bond will form Nitrogen and Tellurium

Chemistry
1 answer:
sineoko [7]3 years ago
4 0

Answer: Vander waals

Explanation:

Tellurium is a chemical element with atomic number 52. It's symbol is Te.

Nitrogen is a chemical element with atomic number 14. Its symbol is N

VANDER WAALS bond is found between Nitrogen and Tellurium, just as in Tellurium(II) Nitrogen.

This bond is relatively weak compared to some other kinds of bonds.

That is why tellurium and most of its compounds are usually brittle and easily grounded.

So, Vander Waals bonds is the answer

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Explanation:

Binding energy = ( Δm * 931.5 ) MeV

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Δm  = 2.0165 u - 2.0141 u = 2.4 * 10^-3 u

∴ Binding energy per nucleon = ( 2.4 * 10^-3  * 931.5 ) MeV / 2 nucleons

                                                  = 1.12 MeV / nucleon

<u>b) ⁷Li = 3 protons , 4 neutrons = 7 nucleons </u>

theoretical mass = 7.0160 u

Actual mass = ( 3 * 1.0078 ) + ( 4 * 1.0087 )  = 7.0582 u  

Δm  = ( 7.0582 u  - 7.0160 u  ) = 0.0422 u

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                                                  = 5.62 MeV / nucleon

<u>C) ⁶²Ni = 28 protons , 34 neutrons = 62 nucleons </u>

Theoretical mass = 61.9283 u

Actual mass = ( 28 * 1.0078 ) u + ( 34 * 1.0087 ) u

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Δm = 0.5859 u  

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Actual mass = ( 48 * 1.0078 ) + ( 62 * 1.0087 )

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∴ Binding energy per nucleon = ( 1.0108 * 931.5 ) / 110

                                                  = 8.56 MeV / nucleon

hence we can conclude that the binding energy has a maximum value for nuclei with a mass around 60

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