Answer:
the answer should be D, I'm so sry if its not
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to

sq. units.
Answer:
1.A - B
1.B - D
1.C - [unsure]
Step-by-step explanation:
Find the slope of the original line, and use the slope-intercept from y= mx+b to find the line parallel to y = 4.
y = 0 + 5