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UkoKoshka [18]
3 years ago
11

With the water trap being used, all the possible sources of error would be eliminated.

Physics
1 answer:
Phoenix [80]3 years ago
7 0

Answer:

True

Explanation:

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A solenoid that is 133 cm long has a radius of 2.99 cm and a winding of 1740 turns; it carries a current of 3.91 A. Calculate th
erica [24]

Answer:

The value is  B = 0.0643 \ T  

Explanation:

From the question we are told that

   The length of the solenoid is  L =  133 \  cm  = 1.33 \  m

     The radius is  r = 2.99 \  cm   = 0.0299 \  m

     The number of turns is N  = 1740 \ turns

     The current it carries is  I = 3.91 \ A

Generally the magnitude of the magnetic field is mathematically represented as

           B = \frac{\mu_o *  N  * I}{L}

Here  \mu_o  is the permeability of free space with value  \mu_o = 4\pi *10^{-7} \ N/A^2

=>      B = \frac{  4\pi * 10^{-7} * 1740  * 3.91}{0.133}  

=>      B = 0.0643 \ T  

5 0
3 years ago
What do you think would be the most important thing to know about understanding the life of Sioux (Lakota) children?
Tcecarenko [31]
The main idea word to know is the Life of Sioux (Lakota) children 
4 0
3 years ago
A 2-kg wood block is pulled by a string across a rough horizontal floor. The string exerts a tension force of 30 N on the block
Luden [163]

Answer:

Work done, W = 84.57 Joules

Explanation:

It is given that,

Mass of the wooden block, m = 2 kg

Tension force acting on the string, F = 30 N

Angle made by the block with the horizontal, \theta=20^{\circ}

Distance covered by the block, d = 3 m

Let W is the work done by the tension force. It can be calculated as :

W=F\ cos\theta\times d

W=30\times cos(20)\times 3

W = 84.57 Joules

So, the work done by the tension force is 84.57 Joules. Hence, this is the required solution.

7 0
3 years ago
A box is 30cm wide , 50cm long and 20cm high Calculate :
stellarik [79]

Answer:

A) 1500cm ^2

B) 30000 CM ^3

7 0
3 years ago
The drinking water needs of an office are met by cooling tab water in a refrigerated water fountain from 23 to 6°C at an average
Ratling [72]

Answer:

The correct option is;

(c) 64W

Explanation:

Here we have the Coefficient Of Performance, COP given by

COP = \frac{Q_{cold}}{W} = 3.1

The heat change from 23° to 6°C for a mass of 10 kg/h which is equivalent to 10/(60×60) kg/s or 2.78 g/s we have

Q_{cold} = m·c·ΔT = 2.78 × 4.18 × (23 - 6) = 197.39 J

Therefore, plugging in the value for  Q_{cold} in the COP equation we get;

COP = \frac{197.39 }{W} = 3.1 which gives

W =  \frac{197.39 }{3.1} = 63.674 \ J

Since we were working with mass flow rate then the power input is the same as the work done per second and the power input to the refrigerator = 63.674 J/s ≈ 64 W.

The power input to the refrigerator is approximately 64 W.

4 0
3 years ago
Read 2 more answers
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