With the water trap being used, all the possible sources of error would be eliminated.

A cat dozes on a stationary merry-go-round, at a radius of 4.4 m from the center of the ride. The operator turns on the ride and

monitta

Answer:

The coefficient of static friction is 0.29

Explanation:

Given that,

Radius of the merry-go-round, r = 4.4 m

The operator turns on the ride and brings it up to its proper turning rate of one complete rotation every 7.7 s.

We need to find the least coefficient of static friction between the cat and the merry-go-round that will allow the cat to stay in place, without sliding. For this the centripetal force is balanced by the frictional force.

$\mu mg=\dfrac{mv^2}{r}$

v is the speed of cat, $v=\dfrac{2\pi r}{t}$

$\mu=\dfrac{4\pi^2r}{gt^2}\\\\\mu=\dfrac{4\pi^2\times 4.4}{9.8\times (7.7)^2}\\\\\mu=0.29$

So, the least coefficient of static friction between the cat and the merry-go-round is 0.29.

4 0

3 years ago

Which is likely to be more common in our Galaxy: white dwarfs or black holes? Why?

Nookie1986 [14]

Answer:

White dwarfs are likely to be much more common. The number of stars decreases with increasing mass, and only the most massive stars are likely to complete their lives as black holes. There are many more stars of the masses appropriate for evolution to a white dwarf.

4 0

3 years ago

Question 1 of 20

jolli1 [7]

Answer:

B

Explanation:

5 0

2 years ago

Read 2 more answers

A ball is kicked from the top of a building with a velocity of 50 m/s and lands 165 m away from the base of the buildi

solniwko [45]

Answer:

32.3 m/s

Explanation:

The ball follows a projectile motion, where:

- The horizontal motion is a uniform motion at costant speed

- The vertical motion is a free fall motion (constant acceleration)

We start by analyzing the horizontal motion. The ball travels horizontally at constant speed of

$v_x = 50 m/s$

and it covers a distance of

d = 165 m

So, the total time of flight of the ball is

$t=\frac{d}{v_x}=\frac{165}{50}=3.3 s$

In order to find the vertical velocity of the ball, we have now to analyze its vertical motion.

The vertical motion is a free-fall motion, so the ball is falling at constant acceleration; therefore we can use the following suvat equation:

$v_y = u_y +at$

where

$v_y$ is the vertical velocity at time t

$u_y=0$ is the initial vertical velocity

$a=g=9.8 m/s^2$ is the acceleration of gravity (taking downward as positive direction)

Substituting t = 3.3 s (the time of flight), we find the final vertical velocity of the ball:

$v=0 + (9.8)(3.3)=32.3 m/s$

5 0

3 years ago

radio waves travel at the speed of light, 3 x 10^8 m/s. the wavelength of a radio wave record is 200,000,000 hz is?

ludmilkaskok [199]

Answer:

1.5m

Explanation:

Speed of waves is given as the product of the wavelength and frequency. Sometimes when frequency is not given but the period is given, we get the frequency as the reciprocal of the period. The speed of waves is given in m/s, wavelength in m while frequency in Hz.

Speed, s= fw and making w the subject of formula,

$w=\frac {s}{f}$

Substituting 300, 000, 000 m/s for s and 200, 000, 000 for f then we obtain that

$w=\frac {300000000}{200000000}=1.5 m$

6 0

3 years ago