Answer:
(2R,3S)-2-ethoxy-3-methylpentane
and
(2S,3S)-2-ethoxy-3-methylpentane
Explanation:
For this case, we will have
as nucleophile. Also, this compound is also in excess. So, we will have as solvent
a protic solvent. Therefore the Sn1 reaction would be favored.
The first step would be the carbocation formation followed by the attack of the nucleophile. In this case both isomers would be produced: R and S (see figure).
Can you type it out the picture is too blurry to read, sorry.
Answer:
potassium hydroxide + sulfuric acid → potassium sulfate + water.
Explanation:
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Answer:d
Explanation: over time water evaporates which leaves you with the white crystals mass