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adell [148]
3 years ago
13

What word describes the equal shares of a shape

Mathematics
2 answers:
horrorfan [7]3 years ago
8 0

Answer:

The word usually depends on how many equal shares there are. Like if there are two equal shares, then word “halves” is used and so on.

Further details:

Dividing circles and rectangles into two, three, or four equal shares, refer to the shares using the words halves, thirds, half of, a third of, etc., and pronounce the whole as two halves, three thirds, four fourths. Be aware of that equal shares of identical wholes need not have the same shape.

Halves:

If a form is divided into two equal shares, the shares can be designated as halves.

One of the shares can be designated as half of the entire shape.

The whole shape can be labeled as two halves.

Thirds:

If a form is divided into three equal shares, the shares can be designated as thirds.

One of the shares can be labeled as a third of the whole shape.

The whole shape can be labeled as three thirds.

Fourths:

If a shape is divided into four equal shares, the shares can be designated as fourths.

One of the shares can be designated as a fourth of the whole shape.

The entire shape can be labeled as four fourths.

Answer details:

Subject: Mathematics

Level:  Middle school

Keywords:

• Partition of words

• Halves

• Equal shares of shape

• Shares

Learn more to evaluate:

brainly.com/question/4435403

brainly.com/question/12896802

brainly.com/question/1617285

Sloan [31]3 years ago
4 0
The word will depend on how many equal shares there are. For example, if there are two equal shares, you can say "halves"; if there are three equal shares, you can say "thirds"; if there are four equal shares, you can say "quarters," etc.
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Write and equati9n of a l8ne that passes through (1,-2) and is perpendicular to -4x+7y=21
yarga [219]

Given:

A line passes through (1,-2) and is perpendicular to -4x+7y=21.

To find:

The equation of that line.

Solution:

We have, equation of perpendicular line.

-4x+7y=21

Slope of this line is

m_1=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}

m_1=-\dfrac{-4}{7}

m_1=\dfrac{4}{7}

Product of slope of two perpendicular lines is -1.

m_1\times m_2=-1

\dfrac{4}{7}\times m_2=-1

m_2=-\dfrac{7}{4}

Now, slope of required line is -\dfrac{7}{4} and it passes through (1,-2). So, the equation of line is

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where, m is slope.

y-(-2)=-\dfrac{7}{4}(x-1)

4(y+2)=-7(x-1)

4y+8=-7x+7

4y+7x=7-8

7x+4y=-1

Therefore, the equation of required line is 7x+4y=-1.

7 0
2 years ago
Math: what is 2+7-9+11=
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