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adell [148]
3 years ago
12

C. If 150 grams of oxygen are produced, how many moles of sodium chlorate decomposed

Chemistry
1 answer:
Black_prince [1.1K]3 years ago
7 0

Answer:

3.13 moles of sodium chlorate are decomposed.

Explanation:

Given data:

Mass of oxygen produced = 150 g

Number of moles of sodium chlorate decomposed = ?

Solution:

Chemical equation:

2NaClO₃   →   2NaCl + 3O₂

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 150 g/ 32 g/mol

Number of moles = 4.7 mol

Now we will compare the moles of oxygen with sodium chlorate.

                     O₂           :           NaClO₃

                      3             :              2

                    4.7            :          2/3×4.7 = 3.13 mol

3.13 moles of sodium chlorate are decomposed.

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For the hypothetical reaction: A + B ---&gt; 2C, write an expression that relates the disappearance of A and B to the appearance
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Rate expression has been given below

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If 2.00 moles of H₂ and 1.55 moles of O₂ react how many moles of H₂O can be produced in the reaction below?
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