The amount of force applied per unit area is known as which of the following?

Chemistry

1 answer:

Anon25 [30]3 years ago

5 0

A:pressure because it's the force that presses us down to earth which is also gravity.

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HELP ASAP *SCIENCE* pls do it fast! WITH PROOF

goldenfox [79]

Answer:

a toster

Explanation:

3 0

3 years ago

Please Help! Check the following problem for errors. If you find an error, identify it, tell why it is an error and correct the

Wewaii [24]

The question says only to convert the Zn(OH)₂ into moles. But the given answer has many errors such as formula, mass and moles.

The corrected answer is as follows.

Moles (mol) = mass (g) / molar mass (g/mol)

Mass of Zn(OH)₂ = 0.45 g
Molar mass of Zn(OH)₂ = 99.424 g/mol
Hence, moles of Zn(OH)₂ = 0.45 g / 99.424 g/mol
 = 4.526 x 10⁻³ mol

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3 years ago

4-methyl-3-hexanol was prepared by reacting an alkene with either hydroboration-oxidation or oxymercuration-reduction. Draw the

Ivenika [448]

Answer:

Structure in attachment.

Explanation:

The oxymercuration-demercuration of an asymmetric alkene usually produces the Markovnikov orientation of an addition. The electrophile ⁺Hg(OAc), formed by the electrophile attack of the mercury ion, remains attached to least substituted group at the end of the double bond. This electrophile has a considerable amount of positive charge on its two carbon atoms, but there is more positive charge on the more substituted carbon atom, where it is more stable. The water attack occurs on this more electrophilic carbon, and the Markovnikov orientation occurs.

In hydroboration, borane adds to the double bond in one step. Boron is added to the less hindered and less substituted carbon, and hydrogen is added to the more substituted carbon. The electrophilic boron atom adds to the less substituted end of the double bond, positioning the positive charge (and the hydrogen atom) at the more substituted end. The result is a product with the anti-Markovnikov orientation.