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Anuta_ua [19.1K]
3 years ago
6

A wire is joined to points X and Y in the circuit diagram shown.How does the circuit change when the wire is added?

Physics
2 answers:
svetoff [14.1K]3 years ago
8 0

Answer: C i did it on ED

Explanation:

spayn [35]3 years ago
6 0

Answer:C. A short circuit occurs and makes bulbs 3 and 4 turn off but keeps bulbs 1 and 2 lit

Explanation:

edge 2021

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How much charge passes through a wire in 4.0 s if the current is 3.0 A?
NemiM [27]

Answer:

12 coloumbs

Explanation:

Q = IT

I= 3A, T=4s

Q = 3×4 =12coloumbs

6 0
3 years ago
A 30-m-long rocket train car is traveling from Los Angeles to New York at 0.5c when a light at the center of the car flashes. Wh
Novosadov [1.4K]

Given that,

Distance =30 m

speed = 0.5c

(A). We need to find the bell and siren simultaneous events for a passenger seated in the car

According to given data

The distance travelled by the light to reach either side of the rocket  train car is same.

So, The two events are simultaneous and the bell and siren are the simultaneous events for a passenger seated in the car.

(B). We need to calculate time interval between the events

Using formula of time dilation

\Delta t=\dfrac{\Delta t'}{\sqrt{1-\dfrac{v^2}{c^2}}}.....(I)

Where, \delta t' = proper time

\delta t = time interval between the events

The time interval between the events measured in a reference frame

The proper time in this case is

\Delta t'=\Delta t_{1}-\dfrac{v\Delta x}{c^2}

For the second interval,

Put the value of \Delta t' in the equation (I)

\Delta t_{2}=\dfrac{\Delta t_{1}-\dfrac{v\Delta x}{c^2}}{\sqrt{1-\dfrac{v^2}{c^2}}}

Put the value in the equation

\Delta t_{2} = \dfrac{0-\dfrac{0.5c\times30}{c^2}}{\sqrt{1-\dfrac{0.5^2c^2}{c^2}}}

\Delta t_{2}=\dfrac{-15}{3\times10^{8}\sqrt{1-0.25}}

\Delta t_{2}=-5.77\times10^{8}\ s

Negative sign shows the siren rings before the bell ring.

Hence, (A). Yes, the bell and siren are simultaneous events.

(B). The siren sounds before the bell rings.

8 0
3 years ago
Two charges, -20 C and +4.7 C, are fixed in place and separated by 3.0 m. a. At what spot along a line through the charges is th
Pani-rosa [81]

The zero net electric field point is at a point that is 0.98 m away from 4.7C charge.If a 14C charge is placed at this point then, force acted on the charge placed at this point is equal to zero.

Explanation:

Let at A both net electric field is zero then

At A ,E1=E2

E1=k*Iq1I / (d+x)^2

E2=k*Iq2I /x^2

Equating both

6 0
4 years ago
50 points if brainliest !!!!!!!!!!
Natasha_Volkova [10]

Answer:

weight = mg \\  = 70 \times 10 \\  = 700 \: newtons

force = 700 \: newtons

force = mass \times acceleration \\ 700 = 70 \times a \\ a = 10 \:  {ms}^{ - 2}

4 0
3 years ago
A ball moving with an initial velocity of 5 m/s comes to rest after 2s. What was the ball's acceleration?
Inga [223]

Answer:

-2.5m/s²

Explanation:

The acceleration of a body is giving by the rate of change of the body's velocity. It is given by

a = Δv / t        ----------------(i)

Where;

a = acceleration (measured in m/s²)

Δv = change in velocity = final velocity - initial velocity   (measure in m/s)

t = time taken for the change (measured in seconds(s))

From the question;

i. initial velocity = 5m/s

final velocity = 0 [since the body (ball) comes to rest]

Δv = 0 - 5 = -5m/s

ii. time taken = t = 2s

<em>Substitute these values into equation (i) as follows;</em>

a = (-5m/s) / (2s)

a = -2.5m/s²

Therefore, the acceleration of the ball is -2.5m/s²

NB: The negative sign shows that the ball was actually decelerating.

6 0
3 years ago
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