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victus00 [196]
3 years ago
10

20. The model of the universe that suggests that the sun is the center of the universe was first brought by

Physics
1 answer:
Damm [24]3 years ago
3 0
A. Copernicus was the first one to suggest a heliocentric model of the universe
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A race car accelerates from 0.00m/s to 40.0m/s with a displacement of 50.0m. What was the cars
Vladimir79 [104]

Answer:

Explanation:

Using the equation of motion v² = u²+2as

v is the final velocity = 40m/s

u is the iniyail velocity 0m/s

a is the acceleration

s is the displacement

Substituting in the formula;

40² = 0²+2a(50)

1600 = 100a

Divide both sides by 100

100a/100 = 1600/100

a = 16

Hence the car acceleration is 16m/s²

7 0
3 years ago
In which type of wave do the particles in a medium move perpendicular to the direction that the wave moves?
vredina [299]
A.transverse waves....
3 0
3 years ago
A rocket is launched at an angle of 39◦ above the horizontal with an initial speed of 90 m/s. It moves for 7 s along its initial
vagabundo [1.1K]

Answer:

Y=1370.23m

Explanation:

The motion have two moments the first one the time the initial velocity is accelerating then when the engines proceeds to move as a projectile

a=19 \frac{m}{s^{2} } \\voy=vo*sin(\alpha )\\voy=90*sin(39 )\\y_{o}=0m\\y_{f}=y_{o}+v_{oy}*t+\frac{1}{2}*a*t^{2}\\y_{f}=90*sin(39)*7s+\frac{1}{2}*19\frac{m}{s^{2} }*(7)^{2}\\y_{f}=861.97m

Now the motion the rocket moves as a projectile so:

v_{fy}=v_{iy}+a*t\\v_{fy}=90+9.8*7\\v_{fy}=158.6 sin(39)

Now the final velocity is the initial in the second one

v_{fy}^{2}=v_{fi}^{2}+2*a*yf \\\\a=g\\

The maximum altitude Vf=0

0=v_{fi}^{2}+2*a*yf \\\\yf=\frac{(158.6 sin(39))^{2} }{2*9.8\frac{m}{s^{2} } } \\yf=508.26m

So total altitude is both altitude of the motion so:

Y=508.2m+861.97m\\Y=1370.23m

6 0
4 years ago
On a roller coaster ride at an amusement park, a car travels from 7.6 m/s to 56 m/s in 3 seconds. whats the cars acceleration?
nataly862011 [7]

Acceleration is defined as rate of change in velocity

So we can write its formula as

a = \frac{v_f - v_i}{t}

here we know that

v_f = final velocity = 56 m/s

v_i = initial velocity = 7.6 m/s

t = time interval to change the velocity = 3 s

now we will plug in all values in the above equation

a = \frac{56 - 7.6}{3}

a = \frac{48.4}{3}

a = 16.13 m/s^2

so here roller coaster will accelerate at rate of 16 m/s^2 and hence correct answer is "option d"

3 0
3 years ago
What are three type of pedestrians you should pay special attention to while driving
sveticcg [70]

The answer is :



Children

Mature Pedestrians

Runners/Joggers

5 0
3 years ago
Read 2 more answers
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