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irakobra [83]
3 years ago
5

The sample concentration was measured at 50mg/ml. The loading concentration needs to be 10mg/ml. The final volume needs to be 25

ul. What is the volume of sample needed and the amount of buffer needed to reach 25ul
Chemistry
1 answer:
Svet_ta [14]3 years ago
3 0

Answer:

a)  V_1=5ul

b)  v=20ul

Explanation:

From the question we are told that:

initial Concentration C_1=50mg/ml

Final Concentration C_2=10mg/ml

Final volume needs V_2 =25ul

Generally the equation for Volume is mathematically given by

C_1V_1=C_2V_2

V_1=\frac{C_1V_1}{C_2}

V_1=\frac{10*25}{50}

V_1=5ul

Therefore

The volume of buffer needed is

v=V_2-V_1\\\\v=25-5

v=20ul

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