Question

The sample concentration was measured at 50mg/ml. The loading concentration needs to be 10mg/ml. The final volume needs to be 25ul. What is the volume of sample needed and the amount of buffer needed to reach 25ul

Answer 1

Answer:

a)  $V_1=5ul$

b)  $v=20ul$

Explanation:

From the question we are told that:

initial Concentration $C_1=50mg/ml$

Final Concentration $C_2=10mg/ml$

Final volume needs $V_2 =25ul$

Generally the equation for Volume is mathematically given by

$C_1V_1=C_2V_2$

$V_1=\frac{C_1V_1}{C_2}$

$V_1=\frac{10*25}{50}$

$V_1=5ul$

Therefore

The volume of buffer needed is

$v=V_2-V_1\\\\v=25-5$

$v=20ul$