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hodyreva [135]
3 years ago
9

Jonathan is studying solutions in his chemistry class. The teacher instructs the students to measure 2 tablespoons of salt into

a beaker. Next, Jonathan is told to measure 4 times that amount of water and add it to the beaker. How much water should Jonathan add to the beaker?
tablespoons
Physics
1 answer:
bulgar [2K]3 years ago
3 0
8 tablespoons of water.
2 x 4 = 8

I hope this helps :)
You might be interested in
In physical science lab, Ben and Jerry added small pieces of magnesium to hydrochloric acid. They noticed that bubbles formed, t
svetoff [14.1K]
The signs of a chemical reaction are bubbles, heat an magnesium disappearing.
6 0
4 years ago
A golf ball strikes a hard, smooth floor at an angle of 28.2 ° and, as the drawing shows, rebounds at the same angle. The mass o
WITCHER [35]

Answer:

    I = 1.06886  N s

Explanation:

The expression for momentum is

          I = F t = Δp

therefore the momentum is a vector quantity, for which we define a reference system parallel to the floor

Let's find the components of the initial velocity

          sin 28.2 = v_y / v

          cos 28.2=  vₓ / v

          v_y = v sin 282

          vₓ = v cos 28.2

          v_y = 42.8 sin 28.2 = 20.225 m / s

          vₓ = 42.8 cos 28.2 = 37.72 m / s

since the ball is heading to the ground, the vertical velocity is negative and the horizontal velocity is positive, it can also be calculated by making

θ = -28.2

         v_y = -20.55 m / s

         v_x = 37.72 m / s

X axis

         Iₓ = Δpₓ = p_{fx} - p_{ox}

since the ball moves in the x-axis without changing the velocity, the change in moment must be zero

         Δpₓ = m v_{fx} - m v₀ₓ = 0

          v_{fx} = v₀ₓ

therefore

          Iₓ = 0

Y axis  

        I_y = Δp_y = p_{fy} -p_{oy}

when the ball reaches the floor its vertical speed is downwards and when it leaves the floor its speed has the same modulus but the direction is upwards

         v_{fy} = - v_{oy}

         Δp_y = 2 m v_{oy}

         Δp_y = 2 0.0260 (20.55)

         \Delta p_{y} = 1.0686 N s

the total impulse is

          I = Iₓ i ^ + I_y j ^

          I = 1.06886  j^ N s

7 0
3 years ago
In a basketball game, a player shoots a jump shot. What force actually causes the player to jump into the air? Question 3 option
Julli [10]

Option B is the correct answer.

In a basketball game, a player shoots a jump shot then the floor pushes up on the player.

<h3>Newton's Third Law</h3>

Newton's third law states that when two bodies interact with each other, they apply forces to one another that are equal in magnitude and opposite in direction. The third law is also known as the law of action and reaction.

In the given situation, a player shoots a jump shot. It means that the player pushes the floor downward direction.

Newton's third law is applicable in this situation where the player pushes the floor downward direction, at the same time the floor pushes the player upward. The amount of force applied to the floor by the player is equal in magnitude and opposite in direction as compared to the force applied to the player by the floor.

Hence the option B is the correct answer.

To know more about Newton's third law, follow the link given below.

brainly.com/question/974124.

6 0
3 years ago
You have a remote-controlled car that has been programmed to have velocity v⃗ =(−3ti^+2t2j^)m/s, where t is in s. At t = 0 s, th
DiKsa [7]

Answer:

The y-component of the car's position vector is 670m/s.

The x-component of the acceleration vector is -3, and the y-component is 40.

Explanation:

The displacement vector of the car with velocity

\boldsymbol{v}= (-3t\boldsymbol{i}+2t^2\boldsymbol{j})m/s

is the integral of the velocity.

Integrating \boldsymbol{v} we get the displacement vector \boldsymbol{d}:

\boldsymbol{d}=(-\dfrac{3}{2}t^2\boldsymbol{i}+\dfrac{2}{3}t^3\boldsymbol{j}  )

Now if the initial position if the car is

\boldsymbol{r}= (3.0\boldsymbol{i}+2.0\boldsymbol{j})

then the displacement of the car at time t is

\boldsymbol{d(t)}= \boldsymbol{r+d}

\boxed{\boldsymbol{d(t)}=(-\dfrac{3}{2}t^2+3.0\boldsymbol{i}+\dfrac{2}{3}t^3+2.0\boldsymbol{j}  )}

Now at t=10s, we have

\boxed{\boldsymbol{d(t)}=(-147\boldsymbol{i}+670\boldsymbol{j}  )}m

The y-component of the car's position vector is 670m/s.

The acceleration vector is the derivative of the velocity vector:

\boldsymbol{a(t)}=\dfrac{d\boldsymbol{v(t)}}{dt} =(-3\boldsymbol{i}+4t\boldsymbol{j})

and at t=10s it is

\boldsymbol{a(t)}=(-3\boldsymbol{i}+40\boldsymbol{j})m/s^2

The x-component of the acceleration vector is -3, and the y-component is 40.

5 0
3 years ago
Which of the following forms of energy must an object have if it is moving at a constant velocity?
lbvjy [14]

Answer:

Kinetic energy

Explanation:

5 0
3 years ago
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