A 98-kg fullback is running along at 8.6 m / s when a 76-kg defensive back running in the same direction at 9.8 m / s jumps on h
1 answer:
The total momentum before and after the collision must be conserved.
The total momentum before the collision is:
where m1 and m2 are the masses of the two players, and
and 
their initial velocities. Both are considered with positive sign, because the two players are running toward the same direction.
The final momentum is instead
because now the two players are moving together with a total mass of (m1+m2) and final speed vf.
By requiring that the momentum is conserved
we can calculate vf, the post-collision speed:
and the direction is the same as the direction of the players before the collision.
The total momentum before the collision is:
where m1 and m2 are the masses of the two players, and
The final momentum is instead
because now the two players are moving together with a total mass of (m1+m2) and final speed vf.
By requiring that the momentum is conserved
we can calculate vf, the post-collision speed:
and the direction is the same as the direction of the players before the collision.
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The factors that affect Density are Mass and Volume
From the question we are told that
The piece of wood shown above has a mass of 20 grams.
Wood parameters
2cm
5cm
3cm
Generally the equation for the Volume is mathematically given as
Generally the equation for the Density is mathematically given as
Therefore the factors that affect Density are Mass and Volume
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Answer:
a)
b) north edge will rise up
Explanation:
torque on the coil is given as
where N is number of loop = 9 loops
i is current = 7.80 A
-B -earth magnetic field =
A- area of circular coil
A =0.015 m2
PUTITNG ALL VALUE TO GET TORQUE
b) north edge will rise up