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seraphim [82]
3 years ago
11

Greg’s mom baked 24 brownies for the bake sale. Vinnie’s mom

Physics
2 answers:
Cerrena [4.2K]3 years ago
8 0

Answer:

Brad's mom baked 120 brownies

Explanation:

In the problem it states Brad's mom baked twice as Greg and Vinnie's moms combined.

So first we'll find how much Greg's mom made, she made 24.

Now Vinnie's mom made 36.

Combined that's 60.

And then twice as many just means multiplied by 2 which is 120.

Here's the equation: (24+36)2

I hope this helps you!!

AysviL [449]3 years ago
4 0

(24 + 36) x 2 = 120

simple math. you're welcome.

"college student"

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A friend rides, in turn, the rims of three fast merry-go-rounds while holding a sound source that emits isotropically at a certa
Aliun [14]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The Ranking of the curve according to their speed would be equal Rank because    v_1 =v_2 =v_3

b

 The first frequency would have a higher rank compared to the other two which will have the same ranking when ranked with respect to their angular velocities because

                                w_1 >w_2 = w_3  

c

The ranking of  the second third frequency would be the same but their ranking would be greater than that of the first frequency because

                          r_2 =r_3 >r_1

Explanation:

Mathematically Frequency can be represented as

                         F = \frac{v}{\lambda}

Where \lambda is the wavelength and v is the velocity

   Now looking at the diagram we see that

          For the  first frequency we have

             Let the wavelength be  \lambda_1 = \lambda , and the frequency  F_1 = F

           For  the second frequency

           Let the wavelength be  \lambda_2 = 2 \lambda , and the frequency F_2 = \frac{F}{2}

           For  the third frequency

           Let the wavelength be  \lambda_3 = 2\lambda ,  and the frequency F_3 = \frac{F}{2}

To obtain v for each of the frequency we make v the subject in the equation above for each frequency

  So,

        For the  first frequency we have

                                 v_1 = \lambda_1 F_1 = \lambda F

          For  the second frequency

                               v_2 = \lambda_2 F_2 = 2 \lambda*\frac{F} {2} = \lambda F      

           For  the third frequency

                               v_3 = \lambda_3 F_3 = 2 \lambda*\frac{F} {2} = \lambda F

Hence

The Ranking of the curve according to their speed would be equal Rank because    v_1 =v_2 =v_3

 Mathematically angular speed can be represented as

                           w = 2 \pi f

   For the  first frequency we have

                          w_1 = 2\pi F_1 = 2 \pi F                        

    For  the second frequency

                        w_2 = 2 \pi F_2 = 2 \pi \frac{F}{2}  = \pi F

     For  the third frequency

                      w_3 = 2 \pi F_3 = 2 \pi \frac{F}{2}  = \pi F  

 Hence

          The first frequency would have a higher rank compared to the other two which will have the same ranking when ranked with respect to their angular velocities because

                                w_1 >w_2 = w_3  

Mathematically the relationship between the angular velocity and the linear velocity can be represented as

                            v = wr

                    =>    r = \frac{v}{w}

 Since the linear velocity is constant we have that

                            r \  \alpha \  \frac{1}{w}

This means that r varies inversely to the angular velocity ,What this means for ranking due to the radius is that the ranking of  the second third frequency would be the same but their ranking would be greater than that of the first frequency because

                          r_2 =r_3 >r_1

       

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PLEASE HELP ME WITH THIS ONE QUESTION
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Answer:

B) R1 = 6 V and R2 = 6V

Explanation:

In series, both resistors will carry the same current.

that current will be I = V/R = 12 / (10 + 10) = 0.6 A

The voltage drop across each resistor is V = IR = 0.6(10) = 6 V

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A 150 g sample of brass at 100 °C is placed in a Styrofoam cup of water containing 120 mL of water at 10 °C. No heat is lost to
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Answer:

≈19.144°C.

Explanation:

all the details are in the attachment.

Note, that c₁, m₁, t₁ are the parameters of the sample of brass; c₂, m₂ and t₂ are  the parameters of the sample of water.

P.S. change the provided design according Your requirements.

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In order to calculate momentum we must have the object's
Vlad [161]
You need to have the Mass and velocity
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