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il63 [147K]
2 years ago
12

A boat of mass 225 kg drifts along a river at a speed of 21 m/s to the west.

Physics
1 answer:
garri49 [273]2 years ago
6 0

Explanation:

I=MV

=225×(15- 21)

=225×-5

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Answer:

At low pressure- \mu_{k}=0.02315

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Initial speed, V_{i}=3.3 m/s

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Net horizontal force due to rolling friction F_{net}=\mu_{k} mg where m is mass, g is acceleration due to gravity, \mu_{k} is coefficient of rolling friction

From kinematic relation, V_{f}^{2}- V_{i}^{2}=2ad

For each tire,

V_{f}^{2}- V_{i}^{2}=2\mu_{k}gd

Making \mu_{k} the subject

\mu_{k}=\frac {V_{f}^{2}- V_{i}^{2}}{2gd}

Under low pressure of 40 Psi, d=18 m

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Therefore, \mu_{k}=0.02315

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