A basketball rolls down a hill until it comes to a stop in a ditch
2 answers:
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The cart is moving by simple harmonic motion, and its position at time t is described by
where
A is the amplitude of the oscillation
is the angular frequency
The amplitude of the oscillation corresponds to the maximum displacement of the spring, which corresponds to the initial position where the spring was released:
A=0.250 m
The period of the motion is T=5.67 s, and the angular frequency is related to the period by
Therefore now we can calculate the position of the system at the time t=29.6 s:
where
A is the amplitude of the oscillation
The amplitude of the oscillation corresponds to the maximum displacement of the spring, which corresponds to the initial position where the spring was released:
A=0.250 m
The period of the motion is T=5.67 s, and the angular frequency is related to the period by
Therefore now we can calculate the position of the system at the time t=29.6 s:
Answer:
Image distance of the bug is - 0.4 m
Magnification is 5 times
Image is real and inverted
Solution:
As per the question:
The focal length of the lens, f = 0.1 m
Distance of the bud from the lens, v = 0.08 m
Now,
Using the lens maker formula:
where
v' = distance of the bug's image from the lens
Now,
v' = - 0.4 m
Now,
Magnification of the bug's image is given by:
m =
m =
Since, negative sign shows that inverted image is formed and positive value of magnification shows that real image is formed.