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4 years ago

I will mark brainlest! SO HELP ME M8!

Physics

1 answer:

Eddi Din [679]4 years ago

3 0

1. B

2. H

3. C

4. A

5. F

6. D

7. E

8. G

2) Perpendicular

3) Parallel

Make sure you study this

I'm up to modern physics this was a nice review for me

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What are five examples that illustrate a machine or a person doing work on another?

valentina_108 [34]

I sort of understand but what does it mean by.... Another?

5 0

3 years ago

What would the reaction force of a person be that stands completely still with a mass of 100 kg?

Anastaziya [24]

-981N would be the reaction force of a person be that stands completely still with a mass of 100 kg.

An opposing force to an action force is referred to as a reaction force. The response force that results from surface engagement and adhesion while sliding is known as friction. Usually, the activities of applied forces result in reaction forces and reaction moments.

As,

F = ma

where, F = force

m = mass of object

a = acceleration due to gravity

Plugging in the values we get,

F = 100kg × 9.81m/s

F = 981 N

Since, reaction force acts opposite to action force so the correct answer is -981N.

Learn more about force here;

brainly.com/question/13191643

#SPJ4

4 0

2 years ago

Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also incr

Annette [7]

Answer:

P = 251,916.667 W

Cost = 2,267.25 cents

Explanation:

To solve this question we will use the Work Energy Theorem, which is

$W = dP + dK\\$

Where

$dP$ = Change in Potential Energy

$dK$ = Change in Kinetic Energy

Change in Potential Energy

$P_{i} = mgh_{i}\\ P_{f} = mgh_{f}$

Where

$P_{i}$ = Initial Potential Energy

$P_{f}$ = Final Potential Energy

$m$ = Mass of System = 10,000 kg

$g$ = Acceleration due to gravity = 9.81 m/s

$h_{i}$ = Initial Height = 0

$h_{f}$ = Final Height = 30 m

Inputting the values we get the answer for $dP$

$dP = P_{f} - P_{i}\\dP= mgh_{f} - mgh_{i}\\ dP= 10000(9.81)(30) - 0\\ dP= 2943000$

Change in Kinetic Energy

$K_{i} = \frac{1}{2} mv_{i} ^2\\ K_{f} = \frac{1}{2} mv_{f} ^2$

Where

$K_{i}$ = Initial Kinetic Energy

$K_{f}$ = Final Kinetic Energy

$m$ = Mass of System = 10,000 kg

$g$ = Acceleration due to gravity = 9.81 m/s

$v_{i}$ = Initial Velocity = 0 m/2

$v_{f}$ = Final Velocity = 4 m/s

Inputting the values we get the answer for $dK$

$dK = K_{f} - K_{i}\\ dK = \frac{1}{2} mv_{f} ^2 - \frac{1}{2} mv_{i} ^2\\ dK = \frac{1}{2} (10000)(4)^2 - 0 \\ dK = 80000$

Total Work

$W = dP + dK\\$

Inputting the values

$W = 2943000 + 80000$

$W = 3,023,000$

a) Finding the useful Power Output

$P = \frac{W}{t}$

Where

$P$ = Power Output

$W$ = Work Done = 3,023,000J

$t$ = Time = 12s

Inputting the values

$P = \frac{3,023,000}{12}\\ P = 251,916.667$

P = 251,916.667 W

b) Finding the Total Cost

Cost = $0.0900 x P/1000

Cost = $0.0900 x (251,916.667/1000)

Cost = $22.67 or 2,267.25 cents

4 0

3 years ago

What weather does a occluded front bring?

8090 [49]

Hey I hope this helps in any way.

As the front<span> moves through, cool, fair </span>weather<span> is likely to follow. Warm </span>front<span> Forms when a moist, warm air mass slides up and over a cold air mass. As the warm air mass rises, it condenses into a broad area of clouds. A warm </span>front<span> brings gentle rain or light snow, followed by warmer, milder </span>weather<span>.</span>

6 0

4 years ago

Now you try! Draw the arrows to represent the motion described, then calculate the distance

rewona [7]

<h2>Answer:</h2>

Distance = 27m

Displacement = 3 metres South

<h2>Explanation:</h2>

Distance is a scalar quantity and it represents the length of the path taken by a body.

Displacement is a vector quantity and it represents the distance between the start and end points of a body.

Now to the question:

<em>The car drives 12 metres North i.e</em>

North (+ve)

∧

| 12m

<em>The car then drives 15 metres South i.e</em>

| 15m

∨

South (-ve)

(a) The car's distance d, is just the total distance covered to drive North and then South. i.e

d = 12m + 15m = 27m

(b) The car's displacement D, however takes into respect, the direction of the car as it drives to and fro.

Let North be taken as positive direction

Let South be taken as negative direction.

This means that;

12 m North = +12 m

15 m South = -15m

Therefore;

D = +12 - 15

D = -3m

Since the displacement is negative, then it means that the direction of the total displacement is South.

Therefore, the displacement is 3 metres South

PS: The arrow diagram has also been attached to this response

3 0

3 years ago