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Setler [38]
4 years ago
15

If two balls collide with each other, they will move apart at the same speed if

Physics
2 answers:
denis-greek [22]4 years ago
7 0
A.
if you have seen a newton's cradle this will make sense.

in order for both of them to travel at the same speed, the balls need to have the same mass and the speed to begin with tocontinue to travel at the same speed because mass can affect the impact of the force on the balls by each other, causing each ball to have different speeds.
Kryger [21]4 years ago
6 0
Answer a. would be correct. Since momentum is conserved, Δmv must be constant.
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aivan3 [116]
What are you trying to say?
6 0
4 years ago
How does the strong nuclear force hold the nucleus of an atom together?
erastovalidia [21]

The strong nuclear force holds the nucleus of an atom together.  

Somehow, it overcomes the electrical force of repulsion between protons in the nucleus, which all have the same charge but still stay close together somehow. (b)

3 0
4 years ago
Read 2 more answers
is weigh-in time for the local under-85-kg rugby team. The bathroom scale used to assess eligibility can be described by Hooke’s
yulyashka [42]

Answer:

a) 156960 N/m

b) Yes the player can play on the team.

Explanation:

F = Force

a = Acceleration due to gravity = 9.81 m/s²

m = Mass

k = Spring constant

x = Deformation length of spring

F = ma

From Hooke's law

F=kx\\\Rightarrow ma=kx\\\Rightarrow k=\frac{ma}{x}\\\Rightarrow k=\frac{120\times 9.81}{0.0075}\\\Rightarrow k=156960\ N/m

The effective spring constant is 156960 N/m

When x = 0.48 cm = 0.0048 m

m=\frac{kx}{a}\\\Rightarrow m=\frac{156960\times 0.0048}{9.81}\\\Rightarrow m=76.8\ kg

The mass of the player is 76.8 kg which is less than the required mass limit of the players' which is 85 kg. So, the player is eligible to play.

5 0
3 years ago
a weightlifter lifts a 1000 newton barbell above his head from the floor to a height of 2.5 meters. he holds the barbell there f
solniwko [45]
Work done = Potential Energy  = (mg)h

               mg   =  weight of the ball
 
               = 1000 N * 2.5 m  = 2500 Joules.

The work done during the 5 second is 2500 Joules.       
7 0
3 years ago
1) A fan is to accelerate quiescent air to a velocity of 8 m/s at a rate of 9 m3/s. Determine the minimum power that must be sup
azamat

Answer:

\dot{W} = 339.84 W

Explanation:

given data:

flow Q = 9 m^{3}/s

velocity = 8 m/s

density of air = 1.18 kg/m^{3}

minimum power required to supplied to the fan is equal to the POWER POTENTIAL of the kinetic energy and it is given as

\dot{W} =\dot{m}\frac{V^{2}}{2}

here \dot{m}is mass flow rate and given as

\dot{m} = \rho*Q

\dot{W} =\rho*Q\frac{V^{2}}{2}

Putting all value to get minimum power

\dot{W} =1.18*9*\frac{8^{2}}{2}

\dot{W} = 339.84 W

7 0
3 years ago
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