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monitta
3 years ago
12

What is the average kinetic energy of 1 mole of a gas at -32 degrees Celsius? (R = 8.314 J/K-mol)

Chemistry
1 answer:
romanna [79]3 years ago
3 0

Answer:

3.01 x 103 J

Explanation:

To determine the average kinetic energy of a gas, it is necessary to use the equation, KE = 3/2 RT. The value of R, multiplied by the temperature, and multiplied by 3/2, can provide the average kinetic energy of the gas.

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7 0
3 years ago
Determine the volume, in liters, occupied by 0.015 molecules of oxygen at STp?
Arlecino [84]

5.58 X 10^{-25} Litres is the volume, in liters, occupied by 0.015 molecules of oxygen at STP.

Explanation:

Data given:

molecules of oxygen = 0.015

number of moles of oxygen =?

temperature at STP = 273  K

Pressure at STP = 1 atm

volume = ?

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to convert molecules to moles,

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Applying the ideal gas law since the oxygen is at STP,

PV = nRT

rearranging the equation:

V = \frac{nRT}{P}

putting the values in the rearranged equation:

V = \frac{2.49 X10^{-26}   X 0.08201 X 273}{1}

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5 0
3 years ago
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pantera1 [17]

Answer:

2.2 moles

Explanation:

n = CV

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5 0
2 years ago
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3 years ago
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