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Brums [2.3K]
3 years ago
8

Can calcium or magnesium metal be disposed of down the drain

Chemistry
1 answer:
max2010maxim [7]3 years ago
5 0

<span>We should never dispose pieces of any metal down the drain. We may dispose waste liquids, but not solid metals. They are also considered as hazardous materials and should be thrown to appropriate bins. Calcium or magnesium metal are reactive, flammable solids which could irritate the skin upon contact. Throwing these metals down the drain would be hazardous and<span> careless.</span></span>

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What triggers the small earthquakes that occur around a volcano before an eruption?
bekas [8.4K]
Before<span> the </span>eruption,the fluid pressure from the rising magma (dense liquid) cracks the rocks, the tectonic plates under the Earth's crust are moved and as a result, earthquakes<span> are </span>caused<span>. A lot of </span>small earthquakes<span> in the area near a </span>volcano<span> hint what may </span>happen<span>.</span>
4 0
3 years ago
A polymer sample combines five different molecular-weight fractions, each of equal weight. The molecular weights of these fracti
kakasveta [241]

Answer:

Mn = 43,783

Mw = 60,000

Mz = 73,333

narrow distribution = 1.37

Explanation:

The molecular weights of these fractions increase from 20,000 to 100,000 in increments of 20,000. This means their Mi is respectively: (The molar weight (Mi) of the fractions)

Fraction 1 : Mi = 20  *10^3

Fraction 2: Mi = 40 *10^3

Fraction 3 : Mi = 60 *10^3

Fraction 4: Mi = 80 *10^3

Fraction 5 : Mi = 100  *10^3

The ΣMi = 300*10^-3

The Wi (mass of the fractions is for all the fractions the same, let's say 1)

So Wi = 1+1+1+1+1 = 5

Since number of moles = mass / Molar mass

The number of moles is respectively: ni = Wi/Mi (x10^5)

Fraction 1 : ni = Wi/Mi = 1/20000 = 5

Fraction 2: ni = 1/40000 = 2.5

Fraction 3 : ni =1/60000 = 1.67

Fraction 4: ni = 1/80000 = 1.25

Fraction 5 : ni= 1/100000 = 1

The Σni = 11.42

Mn = ΣWi/ni = 5/11.42*10^-5 = 43,783

Mw = (ΣWi * Mi)/ΣWi  = 300,000 /5 = 60,000

Mz = (ΣWi * Mi²)/ΣWi *Mi = (4*10^8 +16*10^8 +36*10^8 +64*10^8 +100*10^8) /300,000  =73,333

Mz/Mn = narrow distribution =60,000/43,783 = 1.37

7 0
3 years ago
Read 2 more answers
5. A gas occupies 2000. Lat 100.0 K and exerts a pressure of 100.0 kPa. What volume will
Anna [14]

Answer:

4000 L

Explanation:

Step 1:

Data obtained from the question. This include the following:

Initial volume (V1) = 2000 L.

Initial temperature (T1) = 100 K.

Initial pressure (P1) = 100 kPa.

Final temperature (T2) = 400 K.

Final pressure (P2) = 200 kPa.

Final volume (V2) =..?

Step 2:

Determination of the new volume of the gas.

The new volume of the gas can be obtained by using the general gas equation as follow:

P1V1/T1 = P2V2/T2

100 x 2000/100 = 200 x V2/400

Cross multiply to express in linear form.

100 x 200 x V2 = 100 x 2000 x 400

Divide both side by 100 x 200

V2 = (100 x 2000 x 400)/(100 x 200)

V2 = 4000 L

Therefore, the new volume of the gas is 4000 L

5 0
3 years ago
Select the correct answer.
Stels [109]
I would definitely say that the answer is

C. drought

because if they are getting 43.76 inches of rain on average, and then one year they decrease 10.31 inches of rain to 33.45 inches of rain, its a drought for sure.
7 0
3 years ago
Read 2 more answers
You have a sample of each of the following five metals, with the mass and density
Sindrei [870]

Answer:

E) Silver, mass = 420 g, d = 10.5 g/cm.

Explanation:

Hello,

In this case, since the density is defined by:

\rho =\frac{m}{V}

Given the mass and density, we compute the volume via:

V=\rho *m

Thus, for each vase we have:

A) V=135g*2.7g/cm^3=364.5cm^3

B) V=305g*8.92g/cm^3=2720.6cm^3

C) V=240g*7.86g/cm^3=1886.4cm^3

D) V=75g*1.74g/cm^3=130.5cm^3

E) V=420g*10.5g/cm^3=4410cm^3

In such a way, the largest volume corresponds to E) Silver, mass = 420 g, d = 10.5 g/cm.

Best regards.

7 0
3 years ago
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